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zubka84 [21]
2 years ago
11

How do u do this i need help please

Chemistry
2 answers:
Ipatiy [6.2K]2 years ago
3 0

Answer:

i think you should have to mark tick the cell which they lies .for example cell wall is present in plant cell ,so you can mark on plant cell.etc

lozanna [386]2 years ago
3 0
Plant cell : eukaryote
Anime cell : eukaryote
Bacteria: prokaryote
Protist: eukaryote
—————
Plant cell : multicellular
Animal cell : multicellular
Bacteria: multicellular
Protist: unicellular
—————
Plant cell : cell wall
Bacteria: cell wall
Protist: cell wall
———-
Nucleus : plant cell , Animal cell , protist
—————
Vacuole: plant cell
————-
Mitochondrial : plant cell , Anime cell , Bacteria

——-
Plant cell : photosynthesis and respiration
Anime cell : Respiration
Bacteria: respiration and in some bacteria respiration
Protist : respiration
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If the net force on a object is 375 N to the right, in what direction will the object move?
Viktor [21]
To the right
Because there is an unbalanced force in that direction
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8 0
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A. 1.4 m<br> B.1.9m<br> C. 2.4m<br> D. 3.6m
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3 years ago
What is the electron configuration for N (nitrogen)?
ollegr [7]

Answer:

1s^22s^22p^3

Explanation:

Nitrogen has the atomic number = 7

So, No. of electrons = 7

<u><em>Electronic Configuration:</em></u>

1s^22s^22p^3

<u>Remember that:</u>

s sub shell holds upto 2 electrons while p sub shell upto 6

7 0
3 years ago
What is the mass in grams of 1.00 x 10 24 atoms of Mn?
Alex17521 [72]
<h3>Answer:</h3>

91.2 g Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.00 × 10²⁴ atoms Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})
  2. [DA] Multiply/Divide [Cancel out units]:                                                           \displaystyle 91.2321 \ g \ Mn

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

91.2321 g Mn ≈ 91.2 g Mn

7 0
3 years ago
Read 2 more answers
Please help make sure its correct thanks
Wewaii [24]

The empirical formula of metal iodide : CoI₃(Cobalt(III) Iodide)

<h3>Further explanation</h3>

13.02 g sample of Cobalt , then mol Co(MW=58.933 g/mol) :

\tt mol=\dfrac{mass}{Ar}=\\\\mol=\dfrac{13.02~g}{58.933}\\\\mol=0.221

Mass of metal iodide formed : 97.12 g, so mass of Iodine :

\tt =mass~metal~iodide-mass~Cobalt\\\\=97.12-13.02\\\\=84.1~g

Then mol iodine (MW=126.9045 g/mol) :

\tt \dfrac{84.1}{126.9045}=0.663

mol ratio of Cobalt and Iodine in the compound :

\tt 0.221\div 0.663=1\div 3

5 0
3 years ago
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