Which formula is used to find the explicit equation for geometric sequences?

If one pair of opposite sides of a quadrilateral is both congruent and __________, then the quadrilateral is a parallelogram. AN

Sholpan [36]

Answer:

I think it’s parallel

Step-by-step explanation:

Correct me if this is wrong

7 0

3 years ago

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PLease help I have no idea how to this

matrenka [14]

Answer:

y = 3x + 7

Step-by-step explanation:

Parallel lines have the same slope, so you can write the equation y = 3x + b and you have to figure out what b is.

plug in x = -3 and y = -2 into the equation y = 3x + b:

-2 = 3 * -3 + b

-2 = -9 + b

7 = b

So the equation is y = 3x + 7

4 0

3 years ago

Which irrational number is represented by point B?

avanturin [10]

Answer:

B) √229

Step-by-step explanation:

√229 is about 15.13, which is the approximate location of point B.

__

IMO, the dot at point P is a little too far to the right for √229.

6 0

3 years ago

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Please help guys. And if u can help me with this topic farther pls message me for the ig or snap

Setler [38]

Answer:

54

Step-by-step explanation:

108 divided by 2 is 54 making the value of y 4. Hope this helps!

8 0

3 years ago

Uhm mainly 11 and 12 but if u solve all of them I’ll give u brainliest

Dvinal [7]

Question 11)

Answer:

$\log _2\left(63\right)-\log _2\left(9\right)=\log _2\left(7\right)=2.80$

Step-by-step explanation:

Given the expression

$\log _2\left(63\right)-\log _2\left(9\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)-\log _c\left(b\right)=\log _c\left(\frac{a}{b}\right)$

$\log _2\left(63\right)-\log _2\left(9\right)=\log _2\left(\frac{63}{9}\right)$

$=\log _2\left(\frac{63}{9}\right)$

$\mathrm{Divide\:the\:numbers:}\:\frac{63}{9}=7$

$=\log _2\left(7\right)$

$=2.80$

Therefore,

$\log _2\left(63\right)-\log _2\left(9\right)=\log _2\left(7\right)=2.80$

Question 12)

Answer:

$\log \:_2\left(3\right)+\log \:_2\left(15\right)-\log \:_2\left(9\right)=\log \:_2\left(5\right)=2.32$

Step-by-step explanation:

Given the expression

$\log _2\left(3\right)+\log _2\left(15\right)-\log _2\left(9\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)$

$\log _2\left(3\right)+\log _2\left(15\right)=\log _2\left(3\cdot \:15\right)$

$=\log _2\left(3\cdot \:15\right)-\log _2\left(9\right)$

$\mathrm{Multiply\:the\:numbers:}\:3\cdot \:15=45$

$=\log _2\left(45\right)-\log _2\left(9\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)-\log _c\left(b\right)=\log _c\left(\frac{a}{b}\right)$

$\log _2\left(45\right)-\log _2\left(9\right)=\log _2\left(\frac{45}{9}\right)$

$=\log _2\left(\frac{45}{9}\right)$

$\mathrm{Divide\:the\:numbers:}\:\frac{45}{9}=5$

$=\log _2\left(5\right)$

$=2.32$

Therefore,

$\log \:_2\left(3\right)+\log \:_2\left(15\right)-\log \:_2\left(9\right)=\log \:_2\left(5\right)=2.32$

3 0

3 years ago