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algol [13]
3 years ago
9

A family is going on a trip for 3 days. The total cost for the hotel is​ $369. One hundred dollars a day was budgeted for entert

ainment. How much will each day of the trip​ cost?
Mathematics
1 answer:
saul85 [17]3 years ago
6 0

Answer:

223

Step-by-step explanation:

368 divided by 3= 123

123+100= 223

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In 1987 the average price of gasoline was $0.94. Today the price of has is about $3.00. What is the percent increase from 1987 t
NeX [460]

formula for percent of increase:

difference of Original and new price/original price then multiply by 100

2.06/3.00=.69

.69 x 100=

69% is the percent of increase


5 0
4 years ago
The measures of two supplementary angles have a ratio of 4:5. What is the measure of the larger angle?
kherson [118]
First, we know that all supplementary angles add to 180°. Then, since the angles are in the ratio 4:5, we can also represent these angles as 4x and 5x respectively. Both angle measures have the same variable (x) because no matter how large the angles are, they must have a common multiple because they are in a ratio. We can then write the formula 4x+5x=180 and solve for x. First, you combine like terms to get 9x=180. The you divide both sides by 9 to get x=20. Then, we can find both angles to be 80 (4*20) and 100 (5*20) by plugging them into 4x and 5x. Since 100 is larger, that is your answer.

I hope this helps.
3 0
3 years ago
Read 2 more answers
(HURRY I’LL GIVE YOU THE BRAINIEST IF YOU GET IT RIGHT) What is 3 3/4 x 2 1/2 in fractions?
meriva

Answer:

9 3/8

Step-by-step explanation:

or 75/8

8 0
3 years ago
Read 2 more answers
Given sin (-theta) = 1/5 and tan theta = sqrt.6/12
stich3 [128]

Given  sin (\theta) = \frac{1}{5}, andtan \theta = \frac{\sqrt{6} }{12}, then:

cos\theta=\frac{2\sqrt{6} }{5}

<h3> Computations on trigonometric identities</h3>

From the details provided:

sin (\theta) = \frac{1}{5}\ \\\\tan \theta = \frac{\sqrt{6} }{12} \times \frac{\sqrt{6} }{\sqrt{6} }\\\\tan \theta = \frac{\sqrt{6} \times \sqrt{6} }{12 \times \sqrt{6} }\\\\tan \theta =\frac{1}{2\sqrt{6} }

From the relationship above:

Opposite = 1

Adjacent = 2\sqrt{6}

Hypotenuse = 5

cos\theta=\frac{Adjacent}{Hypotenuse} \\\\cos\theta=\frac{2\sqrt{6} }{5}

Learn more on trigonometry here: brainly.com/question/20519838

3 0
3 years ago
I need this answered asap i will mark brainliest.
Harlamova29_29 [7]

I typed right on the problem set.

4 0
3 years ago
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