If an athlete leaps vertically at 4.0m/s, what maximum height does he reach?
1 answer:
Hello
This is a problem of accelerated motion, where the acceleration involved is the gravitational acceleration:
, and where the negative sign means it points downwards, against the direction of the motion.
Therefore, we can use the following formula to solve the problem:
where
is the initial vertical velocity of the athlete, 
is the vertical velocity of the athlete at the maximum height (and 
at maximum height of an accelerated motion) and S is the distance covered between the initial and final moment (i.e., it is the maximum height). Re-arranging the equation, we get
This is a problem of accelerated motion, where the acceleration involved is the gravitational acceleration:
Therefore, we can use the following formula to solve the problem:
where
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Answer:
a) Knowns, initial speed , final speed
and gravity due it is a constant
b) The maximum high reached by the dolphin is
c) Total time is
Explanation:
a) First of all the initial speed is given at the start of the problem, gravity is constant and final speed is known any object thrown straight up reaches its max high at speed.
b) Second, now that we know final speed we use , as we clear for
.
Then we use
c)Third, finally we can use , as we know
when the dolphin fall into the water again and
, then we have
is a quadratic form
so we have
and