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musickatia [10]
3 years ago
6

If an athlete leaps vertically at 4.0m/s, what maximum height does he reach?

Physics
1 answer:
joja [24]3 years ago
3 0
Hello
This is a problem of accelerated motion, where the acceleration involved is the gravitational acceleration: g=-9.81~m/s^2, and where the negative sign means it points downwards, against the direction of the motion.

Therefore, we can use the following formula to solve the problem:
v_f^2 = v_i^2 + 2gS
where v_i=4~m/s is the initial vertical velocity of the athlete, v_f=0 is the vertical velocity of the athlete at the maximum height (and v_f=0~m/s at maximum height of an accelerated motion) and S is the distance covered between the initial and final moment (i.e., it is the maximum height). Re-arranging the equation, we get
S= \frac{v_f^2-v_i^2}{2g}=0.82~m

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