1. The resistor is located at point D.
A resistor is an element of a circuit that opposes to the flow of current through it: the value of its resistance (R) tells how much the resistor opposes to the flow of current, and the resistance is related to the voltage in the circuit (V) and the current (I) by the Ohm's law:
Resistance is measured in Ohm (
), and a resistor is usually represented with a zig-zag line as the one at point D.
2. The switch is located at point B.
A switch is an element of the circuit that can be switched on and off, opening and closing the circuit, therefore allowing or not the flow of current through it. When the switch is open, no current flows; when it is closed, the current can flow through the circuit.
The symbol of a switch is represented at point B.
Answer:
The gravitational force between them is 
.
Explanation:
Given that,
Distance = 1.50 m
Mass of one student = 70.0 kg
Mass of other student = 52.0 kg
We need to calculate the gravitational force
Using formula of gravitational force
Where, m₁ = mass of one student
m₂ = mass of other studen
r = distance between them
Put the value into the formula
Hence, The gravitational force between them is .
Explanation:
The problem doesn't specify that the units have to be g/mL, so you can calculate the density in kg/L without converting the mass or volume.
Just make sure that either way, you write the units.
The acceleration due to gravity near the surface of the planet is 27.38 m/s².
<h3>
Acceleration due to gravity near the surface of the planet</h3>
g = GM/R²
where;
- G is universal gravitation constant
- M is mass of the planet
- R is radius of the planet
- g is acceleration due to gravity = ?
g = (6.626 x 10⁻¹¹ x 2.81 x 5.97 x 10²⁴) / (6371 x 10³)²
g = 27.38 m/s²
Thus, the acceleration due to gravity near the surface of the planet is 27.38 m/s².
Learn more about acceleration due to gravity here: brainly.com/question/88039
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"v0" means that there are no friction forces at that speed
<span>mgsinΘ = (mv0²/r)cosΘ → the variable m cancels </span>
<span>sinΘ/cosΘ = tanΘ = v0² / gr
</span><span>Θ = arctan(v0² / gr) </span>
<span>When v > v0, friction points downslope: </span>
<span>mgsinΘ + µ(mgcosΘ + (mv²/r)sinΘ) = (mv²/r)cosΘ → m cancels: </span>
<span>gsinΘ + µ(gcosΘ + (v²/r)sinΘ) = (v²/r)cosΘ </span>
<span>µ = ((v²/r)cosΘ - gsinΘ) / (gcosΘ + (v²/r)sinΘ) </span>
<span>where Θ is defined above. </span>
<span>When v > v0, friction points upslope: </span>
<span>mgsinΘ - µ(mgcosΘ + (mv²/r)sinΘ) = (mv²/r)cosΘ → m cancels: </span>
<span>gsinΘ - µ(gcosΘ + (v²/r)sinΘ) = (v²/r)cosΘ </span>
<span>µ = (gsinΘ - (v²/r)cosΘ) / (gcosΘ + (v²/r)sinΘ) </span>
<span>where Θ is defined above. </span>
