Mass of methanol (CH3OH) = 1.922 g Change in Temperature (t) = 4.20°C Heat capacity of the bomb plus water = 10.4 KJ/oC The heat absorbed by the bomb and water is equal to the product of the heat capacity and the temperature change. Let’s assume that no heat is lost to the surroundings. First, let’s calculate the heat changes in the calorimeter. This is calculated using the formula shown below: qcal = Ccalt Where, qcal = heat of reaction Ccal = heat capacity of calorimeter t = change in temperature of the sample Now, let’s calculate qcal: qcal = (10.4 kJ/°C)(4.20°C) = 43.68 kJ Always qsys = qcal + qrxn = 0, qrxn = -43.68 kJ The heat change of the reaction is - 43.68 kJ which is the heat released by the combustion of 1.922 g of CH3OH. Therefore, the conversion factor is:
All living things are capable of carrying out all life processes. Some examples of such organisms are plants, animals, microorganisms (such as bacteria)
