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uysha [10]
3 years ago
8

A fluid is a substance that can _____________ and takes the _____________ of its container.

Physics
1 answer:
mezya [45]3 years ago
7 0
Evaporate
Shape

I wish there were provided answer choices. Hope this helped
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Help 30 points and willgive brainliest
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A student wearing frictionless in-line skates on a horizontal surface is pushed, starting from rest, by a friend with a constant
grin007 [14]

Answer:

Physics

Explanation:

Explanation:

We can use the Theorem of Work (W) and Kinetic Energy (K):

W=ΔK=Kf−Ki

it basically tells us that the work done on our system will show up as change in Kinetic Energy:

We know that the initial Kinetic Energy, Ki=12mv2i, is zero (starting from rest) while the final will be equal to 352J; Work will be force time displacement. so we get:

F⋅d=Ff

45d=352

and so:

d=35245=7.8≈8m

8 0
3 years ago
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I NEED HELP PLEASE, THANKS :) What does it mean when white light is diffracted and at a particular location the color seen is bl
alexgriva [62]

Answer:

This is because white light consists of 7 colours with different angles o deviation or retraction.

Explanation:

When a narrow beam of light is refracted by a prism the light spreads into a band of colours (called the spectrum of light )

But in this case if a blue colour is observed it is due to the angle of refraction ,for instance red is refracted the least and hence is seen

4 0
4 years ago
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A small 20-kg canoe is floating downriver at a speed of 2 m/s. What is the canoe’s kinetic energy? A. 40 J B. 80 J C. 18 J
rusak2 [61]

A small 20-kg canoe is floating downriver at a speed of 2 m/s. 40 J is the canoe’s kinetic energy.

Answer: Option A

<u>Explanation:</u>

The given canoe has the mass and is being given to move at a speed. Therefore the kinetic energy of the canoe can be calculated using the following method,

Given that mass of the canoe = 20 kg and its speed =1 m/s

As we know that the Kinetic energy has the formula,

\text {Kinetic energy}=\frac{1}{2} \boldsymbol{m} \boldsymbol{v}^{2}

Therefore, substituting the value into the equation, we get,  

K . E .=\frac{1}{2} \times 20 \times 2^{2} = 40 J

4 0
3 years ago
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An electron is accelrated by a unifor electric field (1000v/m) pointing vertically upward. Use energy methods to get the magnitu
ExtremeBDS [4]

Explanation:

In the given situation two forces are working. These are:

1) Electric force (acting in the downward direction) = qE

2) weight (acting in the downward direction) = mg

Therefore, work done by all the forces = change in kinetic energy

Hence, qE \times S + mg \times S = 0.5 \times mv^{2}

     1.6 \times 10^{-19} \times 1000 + 9.1 \times 10^{-31} \times 9.8 \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2}

It is known that the weight of electron is far less compared to electric force. Therefore, we can neglect the weight  and the above equation will be as follows.

   (1.6 \times 10^{-19} \times 1000) \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2&#10;}

         v = sqrt{\frac{1.6 \times 10^{-19}}{(0.5 \times 9.1 \times 10^{-31})}

           = 592999 m/s

Since, the electron is travelling downwards it means that it looses the potential energy.

8 0
3 years ago
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