The current theory of the structure of the

A frequently quoted rule of thumb in aircraft design is that wings should produce about 1000 N of lift per square meter of wing.

svetlana [45]

Answer:

v₂ = 63.62 m / s

Explanation:

For this exercise in fluid mechanics we will use Bernoulli's equation

P₁ + ρ g v₁² + ρ g y₁ = P₂ + ρ g v₂² + ρ g y₂

where the subscript 1 refers to the inside of the wing and the subscript 2 to the top of the wing.

We will assume that the distance between the two parts is small, so y₁ = y₂

P₁-P₂ = ρ g (v₂² - v₁²)

pressure is defined by

P = F / A

we substitute

ΔF / A = ρ g (v₂² - v₁²)

v₂² = $\frac{\Delta F}{A \ \rho \ g} + v_1^2$

suppose that the area of the wing is A = 1 m²

we substitute

v₂² = $\frac{1000}{1 \ 1.29 \ 9.8} + 63^2$

v₂² = 79.10 + 3969

v₂ = √4048.1

v₂ = 63.62 m / s

7 0

3 years ago

Two gliders are on a frictionless, level air track. Both gliders are free to move. Initially, glider A moves to the right and gl

Yuliya22 [10]

Answer:

The change in momentum of both objects is the same but in opposite direction.

Explanation:

Hi there!

The momentum of the system is calculated as the sum of the momentums of each glider. The momentum of the system is conserved if no external force is acting on the objects (as in this case). That means that the initial momentum of the system is equal to the final momentum of the system.

The momentum of each glider is calculated as follows:

p = m · v

Where:

p = momentum.

m = mass of the glider.

v = velocity.

The momentum of the system for glider A and B can be calculated as follows:

initial momentum = mA · vA + mB · vB

Where:

mA and vA = mass and velocity of glider A

mB and vB = mass and velocity of glider B

Initially, glider B is at rest so that vB = 0. Then, the initial momentum of the system is:

initial momentum = mA · vA

The final momentum of the system is calculated as follows:

final momentum = mA · vA´ + mB · vB´

Where vA´ and vB´ are the final velocities of glider A and B respectively.

We know that mB = 4mA and that vA´ is negative. The the final momentum will be:

final momentum = -mA · vA´ + 4mA · vB´

Since initial momentum = final momentum:

mA · vA = -mA · vA´ + 4mA · vB´

mA · vA + mA · vA´ = 4mA · vB´

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The change in momentum of glider A (ΔpA) is calculated as follows:

ΔpA = final momentum - initial momentum

ΔpA = -mA · vA´ - mA · vA = -mA (vA + vA´) = -4mA · vB´

The change in momentum of glider B (ΔpB) is calculated as follows:

ΔpB = final momentum - initial momentum

ΔpB = 4mA · vB´ - 0 = 4mA · vB´

Then, the change in momentum of both objects is the same but in opposite direction. That´s why the momentum is conserved.

4 0

2 years ago

In a research facility, a person lies on a horizontal platform which floats on a film of air. When the person's heart beats, it

anastassius [24]

Answer: 3.48g

Explanation:

here, we will be using conservation of momentum to solve the problem. i.e the total momentum remains unchanged, unless an external force acts on the system. We'll in thus question, there is no external force acting in the system.

Remember, momentum = mass * velocity, then

mass of blood * velocity of blood = combined mass of subject and pallet * velocity of subject and pallet

Velocity of blood = 56.5cm = 0.565m

mass of blood * 0.565 = 54kg * (0.000063/0.160)

mass of blood * 0.565 = 54 * 0.00039375

mass of blood * 0.565 = 0.001969

mass of blood = 0.00348kg

Thus, the mass of blood that leaves the heart is 3.48g

7 0

3 years ago

Read 2 more answers

g The magnetic force on a charged particle A. depends on the sign of the charge on the particle. B. depends on the velocity of t

Leona [35]

Answer:

E) is described by all of these

Explanation:

The magnetic force on a charged particle is expressed as:

F = qv * B = qvBsinθ

Where,

q = charge on particle

θ = angle between the magnetic field and the particle velocity.

v = velocity of the particle

B = magnitude of field vector

From here, we could denote that magnetic force, F depends on charge on particle, velocity of particle, magnitude of field vector.

The magnetic force on a charged particle is at right angles to both the velocity of the particle. The magnetic force and magnetic field in a charged particle are perpendicular to each other, the right hand rule is used to determine the direction of force.

The correct option is E.

3 0

2 years ago

Read 2 more answers

gayle cooks a roast in her microwave oven. the klystron tube in the oven emits photons whose energy is 1.20 x 10^-3 ev. what are

AveGali [126]

Answer:

$\lambda=1.03\times 10^{-3}\ m$