The current theory of the structure of the

What is the length of an aluminum rod at 65°C if its length at 15°C is 1.2 meters?

lana66690 [7]

Answer:

The new length is 1.20138 m

Explanation:

1- We get the increase in length:

The old length = 1.2 m

The coefficient of expansion of of aluminum is 23 * 10⁻⁶ /K.

The old temperature is 15°C.

The new temperature is 65°C

The increase in length= old length * coefficient of expansion *change in temperature

The increase in length = 1.2 * 23 * 10⁻⁶ * (65-15)

The increase in length = 0.00138 m

2- getting the new length:

new length = old length + increase in length

new length = 1.2 + 0.00138

new length = 1.20138 m

Hope this helps :)

3 0

3 years ago

Read 2 more answers

An object moves in a straight line and is speeding up. Which one of the following statements is true?

kaheart [24]

I could be wrong on this one, but I think the answer is the first option, The net force on the object is in the direction of motion.

Friction can be acting on the object, but if the other force(s) that are acting on the object are greater, I think the object will still be able to accelerate.

The third option can't be true, according to Newton's second law $(f=ma)$ . If there were no forces acting on the object, or if the net forces cancelled each other out, the object wouldn't be accelerating unless its mass was changing.

I suppose the last option is also technically true, but the first is more specific..?

3 0

3 years ago

La magnitud del campo eléctrico E entre dos placas paralelas es 8kN/C. Las placas están separadas 0.03m. ?Cuánto trabajo realiza

olchik [2.2K]

<h2>Respuesta:</h2>

Si tenemos dos placas paralelas y un campo electrico de 8kN/C entre ellas y además conocemos la separación de estas placas que es igual a 0.03m. Entonces, cuando una carga se mueve de un punto a a un punto b el trabajo que es realizado sobre la carga por el campo eléctrico viene dado por la siguiente ecuación:

$W_{a \rightarrow b}=q_{0}E(y_{a}-y_{b})$