A cylindrical wire has a length of 2.80 m and a radius of 1.03 mm. It carries a current of current of 1.35 A, when a a voltage o
1 answer:
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Answer:
44.64 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.8 m/s²
<u>Time taken to reach 1180 m is 11.29 seconds</u>
<u>Time the rocket will keep going up after the engines shut off is 13.06 seconds.</u>
The distance the rocket will keep going up after the engines shut off is 836.05 m
Total distance traveled by the rocket in the upward direction is 1180+836.05 = 2016.05 m
The rocket will fall from this height
<u>Time taken by the rocket to fall from maximum height is 20.29 seconds</u>
Time the rocket will stay in the air is 11.29+13.06+20.29 = 44.64 seconds
Answer:
A) B = 5.4 10⁻⁵ T, B) the positive side of the bar is to the West
Explanation:
A) For this exercise we must use the expression of Faraday's law for a moving body
fem =
fem = - d (B l y) / dt = - B lv
B =
we calculate
B = - 7.9 10⁻⁴ /(0.73 20)
B = 5.4 10⁻⁵ T
B) to determine which side of the bar is positive, we must use the right hand rule
the thumb points in the direction of the rod movement to the south, the magnetic field points in the horizontal direction and the rod is in the east-west direction.
Therefore the force points in the direction perpendicular to the velocity and the magnetic field is in the east direction; therefore the positive side of the bar is to the West