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3 years ago

What relationship is flowers and honey bees

1 answer:

7 0

A symbiotic relationship. One where two species benefit each other. In this case, the flower gives the bee nectar, so the bee pollinates the flower.

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What was the main aim behind Wegener's continental drift theory?

Aleks [24]

D.all of the above is the answer for this question

8 0

3 years ago

John and Caroline go out for a walk one day. This graph represents their distance from home.

Serga [27]

Answer:

Option C is the correct answer.

Explanation:

We have velocity of a body = Change in position/ Time.

Considering first portion of graph,

Change in position = 30 - 0 = 30 m

Time = 0.75 hours = 45 minutes = 2700 seconds

Velocity = 30/2700 = 0.011 m/s

Considering second portion of graph,

Change in position = 30 - 30 = 0 m

Time = 0.5 hours = 30 minutes = 1800 seconds

Velocity = 0/1800 = 0 m/s

Considering third portion of graph,

Change in position = 0 - 30 = -30 m

Time = 0.75 hours = 45 minutes = 2700 seconds

Velocity = -30/2700 = -0.011 m/s

So firstly they walked in one direction(positive direction), then they were still(velocity is zero), then they walked in the opposite direction( velocity is negative).

Option C is the correct answer.

3 0

3 years ago

Read 2 more answers

10. How far does a transverse pulse travel in 1.23 ms on a string with a density of 5.47 × 10−3 kg/m under tension of 47.8 ?????

KATRIN_1 [288]

Answer: Tension = 47.8N, Δx = 11.5× $10^{-6}$ m.

Tension = 95.6N, Δx = 15.4× $10^{-5}$ m

Explanation: A speed of wave on a string under a tension force can be calculated as:

$|v| = \sqrt{\frac{F_{T}}{\mu} }$

$F_{T}$ is tension force (N)

μ is linear density (kg/m)

Determining velocity:

$|v| = \sqrt{\frac{47.8}{5.47.10^{-3}} }$

$|v| = \sqrt{0.00874 }$

$|v| =$ 0.0935 m/s

The displacement a pulse traveled in 1.23ms:

$\Delta x = |v|.t$

$\Delta x = 9.35.10^{-2}*1.23.10^{-3}$

Δx = 11.5× $10^{-6}$

With tension of 47.8N, a pulse will travel Δx = 11.5× $10^{-6}$ m.

Doubling Tension:

$|v| = \sqrt{\frac{2*47.8}{5.47.10^{-3}} }$

$|v| = \sqrt{2.0.00874 }$

$|v| = \sqrt{0.01568}$

|v| = 0.1252 m/s

Displacement for same time:

$\Delta x = |v|.t$

$\Delta x = 12.52.10^{-2}*1.23.10^{-3}$

$\Delta x =$ 15.4× $10^{-5}$

With doubled tension, it travels $\Delta x =$ 15.4× $10^{-5}$ m

4 0

3 years ago

What happens to the force between charges when: (a) the distance between them is halved?<br>

charle [14.2K]

Answer:

i dont know but ill update you

5 0

2 years ago

A car can move from rest to 35 m/s in 5.0 seconds. It's acceleration is

lord [1]

Answer:

A) 7.0 m/s²

Explanation:

Acceleration is found by using the formula:

a = Δv/Δt

This means the change in time divided by the time interval will give us the car's acceleration.

Since the car starts from rest, its initial velocity is 0 m/s. Its final velocity is 35 m/s. The time interval for the car to go from 0 to 35 m/s is 5.0 seconds.

a = (v - v₀)/t

Substitute the final and initial velocity into the formula.

a = (35 - 0)/5
a = 35/5
a = 7

The acceleration of the car is A) 7.0 m/s².

6 0

3 years ago