Question

During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approximately 103 cm/s. The blood volume traverses the aortic arch, exiting with the same speed but opposite direction. Assume the mass density of the blood is 1060 kg/m3 blood, the aortic arch remains stationary, and that the heart rate is 59 bpm. What is the average force exerted by the blood on the wall of the aorta.

Answer 1

Answer:

The value  $F = 0.1396 \ N$

Explanation:

From the question we are told that

   The volume blood  ejected is  $V = 65 \ cm^3 = 65*10^{-6} \ m^3$

    The velocity of the blood ejected is  $v = 103 \ cm/s = \frac{103}{100} = 1.03 \ m/s$

    The density of blood is  $\rho = 1060 \ kg/m^3$

     The heart beat is $R = 59 \ bpm(beats \ per \ minute) = \frac{59}{60}= 0.9833\ bps$

The average force exerted by the blood on the wall of the aorta is mathematically represented as

      $F = 2 * \rho * V * R * v$

=>    $F = 2 * 1060 * 65*10^{-6} * 0.9833 * 1.03$

=>    $F = 0.1396 \ N$