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hichkok12 [17]
2 years ago
5

Identify the type of reaction:

Chemistry
1 answer:
miskamm [114]2 years ago
7 0
It’s #2 because I saw on edigunity 2020
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Which chemical equation demonstrates the law of conservation of mass!
zlopas [31]

Answer:

F. 2NO + 02 —> 2NO

H. 4NH3 + 502 —> 4NO + 6H20

Explanation:

The law of conservation of mass states that matter can neither be created nor destroyed during a chemical reaction but can be convert from one form to another.

2NO + 02 —> 2NO

From the above, the total number of N on the left balance the total number on the right i.e 2 atoms of N on both side of the equation.

The total number of O on the left balance the total number on the right i.e 2 atoms of O on both side of the equation. This is certified by the law of conservation of mass.

4NH3 + 502 —> 4NO + 6H20

From the above, the total number of N on the left balance the total number on the right i.e 4 atoms of N on both side of the equation.

The total number of O on the left balance the total number on the right i.e 10 atoms of O on both side of the equation.

The total number of H on the left balance the total number on the right i.e 12 atoms of O on both side of the equation.

This is certified by the law of conservation of mass.

The rest equation did not conform to the law of conservation of mass as the atoms on the left side did not balance those on the right side

5 0
3 years ago
Assuming that the density of vinegar is 1.005 g/mL, calculate the molatrity of acetic acid in vinegar from an average of 4.6% fo
posledela
Acetic acid is 60.05 grams/mole. In 1 liter of vinegar or 1000 ml  there would be 0.046% of acetic acid = 46 ml x 1.005g/ml = 46.23 grams/60.05 grams= 0.77 moles per litre of vinegar.This then would be the concentration of acetic acid in for example 1 liter of vinegar. 
5 0
3 years ago
How many molecules are there in 21.4 grams of Ca(OH)2?
nata0808 [166]

The answer would be 0.288827452320528

4 0
2 years ago
When does the shape of a molecule affect its polarity?
Aliun [14]

Answer:

I think no C

if wrong correct me pls

4 0
3 years ago
Read 2 more answers
Write the formula of the coordination compound pentaamminecarbonatocobalt(III) iodide. Enclose the coordination complex in squar
7nadin3 [17]

Answer:

[Co(NH3)5CO3]I3

Explanation:

The naming of coordination compounds follows certain rules specified by IUPAC. Usually, the name of the complex makes it quite easy to deduce its structure.

"Pentaamine" means that there are five NH3 ligands as shown in the structure. The ligand carbonato is CO3^2-.  It has no prefix attached to it in the IUPAC name of the complex hence there is only one carbonato ligand present(recall that the complex has a coordination number of six). I did not enclose it within parenthesis as required in the question.

Lastly the III that appeared after the metal name "cobalt" shows its oxidation state. The iodide counter ions must then be 3 in number in order to satisfy this primary valency of the metal hence the inclusion of I3 in the structure of the complex.

6 0
3 years ago
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