Answer:
See explanation
Explanation:
The mechanism for the formation of bromohexane from hexene has been clearly shown in the image attached to this answer.
Hexene is attacked by HBr and a carbocation is first formed as shown. The carbocation is flat and planar. it can be attacked on either face by the bromide ion.
Attack on either faces yields a racemic mixture of the R and S enantiomer as shown in the image.
You can use the mechanism shown to fill in the structures.
Is that chemistry?
Cause I'm kinda confused about how to help you with this question
1) <span>Chemical reactions are always spontaneous when CHANGE IN H is negative and CHANGE IN S is negative</span>False
2)The driving force of a reaction is the change in kinetic energy.
True
3) In the reaction so2cl2 double arrows s02+cl2 heat is evolved. What happens when chlorine (Cl2) is added to the equilibrium mixture at constant volume?
b. The temperature of the system decreases.
4) In a reversible reaction, two substances are in equilibrium if the concentration of each increases by the same amount but the equilibrium constant remains unaffected.
True
5) A numerical value of the ratio of products to reactants, only at a specified temperature is called a(n)
b. equilibrium constant
6)At equilibrium,
a. all reactions have ceased.
Volume = ?
Molarity (M) = 1.00 x 10⁻² M
moles (n) = 3.00 x 10⁻¹ mol
V = n / M
V = 3.00 x 10⁻¹ / 1.00 x 10⁻²
V = 30 L
In this redox reaction, we must identify which is reduced and which is oxidized. Cl is oxidized from -1 to 0, Mn is reduced from +7 to +2.
<span>MnO−4+Cl−→Mn2++Cl2</span>Balance the number of Cl first.
<span>MnO−4+2Cl−→Mn2++C<span>l2
</span></span><span>MnO−4+10Cl−→2M<span>n2+</span>+5C<span>l2
</span></span>Balance the number of oxygen by adding <span>H2O</span>
<span>2MnO−4+10Cl−→2M<span>n2+</span>+5Cl2+8H2O
</span>Balance the number of H by adding H+
<span>2MnO−4+10Cl−+16H+→2M<span>n2+</span>+5Cl2+8H2O
</span>
Now, we know that there are 2 H+ in <span>H2SO4</span>, so, we can get
<span>2MnO−4+10Cl−+8H2SO4→2M<span>n2+</span>+5Cl2+8H2O
</span>
Put <span>S<span>O2−4</span></span> with <span>M<span>n2+</span></span>
<span>2MnO−4+10Cl−+8H2SO4→2MnSO4+5Cl2+8H2O
</span>
Add K in front of <span>MnO−4</span> and <span>Cl−</span> and balance it on the right
<span>2KMnO4+10KCl+8H2SO4→12K++2MnSO4+5C<span>l<span>2 + 8H20
The final answer is </span></span></span>2KMn<span>O4</span><span>+10KCl+8</span><span>H2</span><span>S</span><span>O4</span><span>→6</span><span>K2</span><span>S</span><span>O4</span><span>+2MnS</span><span>O4</span><span>+5C</span><span>l2</span><span>+8</span><span>H2</span><span>O</span>
