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hichkok12 [17]
2 years ago
5

Identify the type of reaction:

Chemistry
1 answer:
miskamm [114]2 years ago
7 0
It’s #2 because I saw on edigunity 2020
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How many neurons does atom in the model shown below have<br> a.2<br> b.9<br> c.10 <br> d.16
const2013 [10]
The atom in the model has 9 neurons.
7 0
2 years ago
Read 2 more answers
What pressure is required to compress 156.0 liters of air at 2.00 atmosphere into a cylinder
garik1379 [7]

Answer:

option B.

Explanation:

Given,

V₁ = 156 L

P₁ =2 atm

Now, in the cylinder

P₂ = ?

V₂ = 36

Using relation between pressure and volume

\dfrac{P_1}{V_2}=\dfrac{P_2}{V_1}

\dfrac{2}{36}=\dfrac{P_2}{156}

P_2 = 8.67\ atm

Hence,  pressure is equal to 8.67 atm.

Hence, the correct answer is option B.

7 0
3 years ago
Which of the following is an example of behavioral variation?
ANTONII [103]

Answer: A, parrots eat seeds, fruit, and nuts, while hawks eat meat.

Explanation:

This option is more onto the behavioral and what the parrots did, while the other options were more on the parrots physical attributions.

<em>I hope this helped! :)</em>

5 0
3 years ago
Convert 59,800 cg/L to g/mL
alexgriva [62]
To convert the given value to the desired one, use the proper unit conversions and dimensional analysis. Use the following conversion for the first set.

    1 g = 100 cg
    1 L = 1000 mL

Using the concept presented above,
         
            V = (59800 cg/L)(1 g/100 cg)1 L/1000 mL)
            V = 0.598 g/mL
6 0
3 years ago
To understand the relation between the strength of an acid or a base and its pKa and pKb values. The degree to which a weak acid
elena-14-01-66 [18.8K]

Answer:

pKa = 3.675

Explanation:

  • pKa = - Log Ka

∴ <em>C</em> X-281 = 0.079 M

∴ pH = 2.40

let X-281 a weak acid ( HA ):

∴ HA ↔ H+ + A-

⇒ Ka = [H+] * [A-] / [HA]

mass balance:

⇒<em> C</em> HA = 0.079 M = [HA] + [A-]

⇒ [HA] = 0.079 - [A-]

charge balance:

⇒ [H+] = [A-] + [OH-]... [OH-] is negligible; it comes from to water

⇒ [H+] = [A-]

∴ pH = - log [H+] = 2.40

⇒ [H+] = 3.981 E-3 M

replacing in Ka:

⇒ Ka = [H+]² / ( 0.079 - [H+] )

⇒ Ka = ( 3.981 E-3 )² / ( 0.079 - 3.981 E-3 )

⇒ Ka = 2.113 E-4

⇒ pKa = - Log ( 2.113 E-4 )

⇒ pKa = 3.675

8 0
3 years ago
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