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vaieri [72.5K]
3 years ago
9

Which statement best describes the properties of covalent compounds?

Chemistry
2 answers:
scZoUnD [109]3 years ago
4 0
B. They may be gases, liquids, or solids at room temp.
WINSTONCH [101]3 years ago
4 0
<h3>Answer </h3>

Option B= They may be gases, liquids, or solids at room temperature, and have a low melting and boiling point.  

<h3>Explanation </h3>

A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding. Hence the bonding is relatively weak thus have low melting and boiling point. On the other hand, ionic compounds are formed by the transferring of electrons thus strong electrostatic forces are present and require a large amount of energy to break it apart hence boiling and melting points are high.

<h3>For example </h3>

The molecule carbon tetrachloride is a non-polar covalent molecule, CCl4. Its melting point is -23°C. By contrast, the ionic solid NaCl has a melting point of 800°C.

<h3>Properties  of Covalent Compounds</h3>

1. Gases, liquids, or solids (made of molecules)  

2. Low melting and boiling points  

3. Poor electrical conductors in all phases  

4. Many soluble in nonpolar liquids but not in water


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how many moles of a nonvolatile, nonelectrolyte solute are required to lower the freezing point of 1000 grams of water by 5.58
Ivan

Answer:

Explanation:

Using freezing point depression formula,

ΔTemp.f = Kf * b * i

Where,

ΔTemp.f = temp.f(pure solvent) - temp.f(solution)

b = molality

i = van't Hoff factor

Kf = cryoscopic constant

= 1.86°C/m for water

= (0 - (-5.58))/1.86

= 3.00 mol/kg

Assume 1 kg of water(solvent)

= (3.00 x 1)

= 3.00 mol.

5 0
3 years ago
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Genrish500 [490]
Is there any more info lol
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8 0
2 years ago
0.415 g of an unknown triprotic acid are used to make a 100.00 mL solution. Then 25.00 mL of this solution is transferred to an
Arturiano [62]

Answer:

Explanation:

Initial burette reading = 1.81 mL

final burette reading = 39.7 mL

volume of NaOH used = 39.7 - 1.81 = 37.89 mL .  

37.89 mL of .1029 M NaOH is used to neutralise triprotic acid

No of moles contained by 37.89 mL of .1029 M NaOH

= .03789 x .1029 moles

= 3.89 x 10⁻³ moles

Since acid is triprotic ,  its equivalent weight = molecular weight / 3

No of moles of triprotic acid = 3.89 x 10⁻³ / 3

= 1.30   x 10⁻³ moles .

8 0
3 years ago
How many ug of nickel (Ni) are required to make 25.00 nanoliters of a 1.25 mol/L solution? Be sure to report your answer to the
devlian [24]

volume of Ni = 25 nL = 25 x 10⁻⁹ L

mol Ni = 25 x 10⁻⁹ L x 1.25 mol/L = 3.125 x 10⁻⁸

mass = mol x Ar Ni

mass = 3.125 x 10⁻⁸ x 59 g/mol

mass = 1.84 x 10⁻⁶ g = 1.84 μg

4 0
2 years ago
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Sugar can be removed from a sugar water solution through dialysis.
Fantom [35]

Answer:

false

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3 years ago
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