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vaieri [72.5K]
4 years ago
9

Which statement best describes the properties of covalent compounds?

Chemistry
2 answers:
scZoUnD [109]4 years ago
4 0
B. They may be gases, liquids, or solids at room temp.
WINSTONCH [101]4 years ago
4 0
<h3>Answer </h3>

Option B= They may be gases, liquids, or solids at room temperature, and have a low melting and boiling point.  

<h3>Explanation </h3>

A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding. Hence the bonding is relatively weak thus have low melting and boiling point. On the other hand, ionic compounds are formed by the transferring of electrons thus strong electrostatic forces are present and require a large amount of energy to break it apart hence boiling and melting points are high.

<h3>For example </h3>

The molecule carbon tetrachloride is a non-polar covalent molecule, CCl4. Its melting point is -23°C. By contrast, the ionic solid NaCl has a melting point of 800°C.

<h3>Properties  of Covalent Compounds</h3>

1. Gases, liquids, or solids (made of molecules)  

2. Low melting and boiling points  

3. Poor electrical conductors in all phases  

4. Many soluble in nonpolar liquids but not in water


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In an exothermic reaction, an increase in temperature favors the formation of products.
pentagon [3]
False, in an exothermic reaction, an increase in temperature does not favor the formation of products. Instead, it favors the backward reaction. An exothermic reaction is a reaction where energy is transferred from the system out to the environment.
7 0
4 years ago
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Describe a procedure to separate a mixture of sugar black pepper and Pebbles
ivolga24 [154]
Dissolve the sugar. Strain the pebbles. You are left with the pepper
8 0
3 years ago
How does the presence of hcl affect the charges on the complexes?
FrozenT [24]

Hydrochloric Acid (HCl) is a strong acid when it is present in the concentrated form but when it is dissolved in water (H_2O) the atoms of this compound dissociates into its respective ions as shown below:

HCl(aq.) + H_2O(aq.) \rightarrow H_3O^+(aq.) + Cl^-(aq.)

When we add HCl to any complex in its concentrated form the complex does not react at all but when its diluted to 6M and is kept for many hours, the complex reacts slowly. For eg:

[Co(NH_3)_6]^3^+(aq.) + HCl(aq.) \rightarrow  [Co(NH_3)_5Cl]^2^+(aq.) + NH_4^+ (aq.)

As seen from the above reaction it can be seen the positive charge on the complex is reduced by 1 unit because one Cl^- ion gets attached to the centre metal atom, therefore we can conclude that the charge on complex gets reduced by 1 unit when HCl reacts with the complex.

7 0
3 years ago
What masses of sodium chloride, magnesium chloride, sodium sulfate, calcium chloride, potassium chloride, and sodium bicarbonate
andreyandreev [35.5K]

Answer:

NaCl: 184g

MgCl₂: 6.60g

Na₂SO₄: 9.26g

CaCl₂: 1.28g

KCl: 0.70g

NaHCO₃: 0.13g

Explanation:

To convert these concentrations to masses we need to convert molarity to moles and moles to grams using molar mass of each salt:

[CaCl₂] = [Ca²⁺] = 0.0115M

[HCO₃⁻] = [NaHCO₃] = 0.0015M

[SO₄²⁻] = [Na₂SO₄] = 0.0652M

[Mg²⁺] = [MgCl₂] = 0.0693M

[K⁺] = [KCl] = 0.0094M

And using the concentration of Cl⁻:

[Cl⁻] = [NaCl] + 2[MgCl₂] + 2[CaCl₂] + [KCl]

[3.32] = [NaCl] + 2[0.0693] + 2[0.0115] + [0.0094]

[NaCl] = 3.149M

The masses you need are:

<em>NaCl (Molar mass: 58.44g/mol):</em>

3.149mol/L * 1L *  (58.44g/mol) =

<h3>184g NaCl</h3><h3 />

<em>MgCl₂ (Molar mass: 95.211g/mol):</em>

0.0693mol/L * 1L *  (95.211g/mol) =

<h3>6.60g MgCl₂</h3><h3 />

Na₂SO₄<em> (Molar mass: 142.04g/mol):</em>

0.0652mol/L * 1L *  (142.04g/mol) =

<h3>9.26g Na₂SO₄</h3>

CaCl₂<em> (Molar mass: 110.98g/mol):</em>

0.0115mol/L * 1L *  (110.98g/mol) =

<h3>1.28g CaCl₂</h3>

KCl<em> (Molar mass: 74.55g/mol):</em>

0.0094mol/L * 1L *  (74.55g/mol) =

<h3>0.70g KCl</h3><h3 />

<em>NaHCO₃ (Molar mass: 84g/mol):</em>

0.0015mol/L * 1L *  (84g/mol) =

<h3>0.13g NaHCO₃</h3>

7 0
3 years ago
Tris base has a molecular weight of 121 g/mol. How many grams of tris base would you need to make 250ml of a 200mM SOLUTION
STatiana [176]

Answer:

6.05 g

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

From the question ,

M = 200mM

Since,

1 mM = 10⁻³ M

M = 200 * 10⁻³ M

V = 250 mL

Since,

1 mL = 10⁻³ L

V = 250 * 10⁻³ L

The moles can be calculated , by using the above relation,

M = n / V  

Putting the respective values ,

200 * 10⁻³ M = n / 250 * 10⁻³ L

n = 0.05 mol

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

m = 121 g/mol

n = 0.05 mol ( calculated above )

The mass of tri base can be calculated by using the above equation ,

n = w / m  

Putting the respective values ,

0.05 mol = w / 121 g/mol

w = 0.05 mol * 121 g/mol

w = 6.05 g

3 0
4 years ago
Read 2 more answers
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