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Alexandra [31]
2 years ago
11

What is the wavelength of the oceans wave

Physics
1 answer:
GREYUIT [131]2 years ago
4 0

Explanation:

the wavelength of a oceans wave depends on the gravity from the moon and the wavelength . sometimes wavelengths are determined by the shapes of the orbits.

sometimes or most of the times wavelengths can also determine the size of the size of water molecules within a wave.

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something that is figurative place where a person locates the source of responsibility in his or her life.
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What is your choses .becuse it mit be a place 


4 0
3 years ago
A glass rod is rubbed briefly with silk and the rod becomes able to attract and lift a number of small pieces of paper. If the r
ser-zykov [4K]

Answer:

it will have a stronger attraction force

Explanation:

8 0
3 years ago
Read 2 more answers
A projectile is launched horizontally off a cliff. If the projectile is launched with more velocity, the time it spends in the a
Sedaia [141]

Answer:

If the projectile is launched horizontally the time it remains in the air will remain constant even if we increase the horizontal velocity.

Explanation:

The vertical displacement will be the same irrespective of the horizontal velocity assuming the projectile is launched from same height. The formula for vertical displacement is given by:

y = v_{oy} - 1/2gt^{2}

where, y = vertical displacement, t = time,

g = acceleration due to gravity,

v_{oy} = Initial vertical velocity

Since, projectile is launched horizontally, therefore v_{oy} = 0

so the equation becomes

y = - 1/2gt^{2}

The above equation shows that time spend in air is not dependent on horizontal launched velocity as there is no horizontal velocity in the formula therefore the time in air will remain constant even if we increase the horizontal velocity.

5 0
3 years ago
The angular displacement of a hoop travels in a circle is 4 rad, the radius of the hoop makes is 0.5m calculate the hoopsTangent
Gnesinka [82]

Hi there!

We can relate linear displacement to angular displacement with the following;

\large\boxed{d = \theta r}

d = tangential/linear displacement (m)

θ = angular displacement (rad)

r = radius (m)

Plug in the givens:

d = (4)(0.5) = \boxed{2.0 m}

8 0
2 years ago
Solve these problems on charges by finding out Q1 and Q2. Q1Q2= 4x10^6, Q1 + Q2 =8.00×10^-6​
inna [77]

Answer:

Answer:

Q_1 = 7Q

1

=7

Q_2 = 10Q

2

=10

Q_3 = 13.5Q

3

=13.5

Step-by-step explanation:

Given

5, 7, 7, 8, 10, 11, 12, 15, 17.

Required

Determine Q1, Q2 and Q3

The number of data is 9

Calculating Q1:

Q1 is calculated as:

Q_1 = \frac{1}{4}(N + 1)Q

1

=

4

1

(N+1)

Substitute 9 for N

Q_1 = \frac{1}{4}(9 + 1)Q

1

=

4

1

(9+1)

Q_1 = \frac{1}{4}*10Q

1

=

4

1

∗10

Q_1 = 2.5th\ itemQ

1

=2.5th item

This means that the Q1 is the mean of the 2nd and 3rd data.

So:

Q_1 = \frac{1}{2}(7+7)Q

1

=

2

1

(7+7)

Q_1 = \frac{1}{2}*14Q

1

=

2

1

∗14

Q_1 = 7Q

1

=7

Calculating Q2:

Q2 is calculated as:

Q_2 = \frac{1}{2}(N + 1)Q

2

=

2

1

(N+1)

Substitute 9 for N

Q_2 = \frac{1}{2}(9 + 1)Q

2

=

2

1

(9+1)

Q_2 = \frac{1}{2}*10Q

2

=

2

1

∗10

Q_2 = 5th\ itemQ

2

=5th item

Q_2 = 10Q

2

=10

Calculating Q3:

Q3 is calculated as:

Q_3 = \frac{3}{4}(N + 1)Q

3

=

4

3

(N+1)

Substitute 9 for N

Q_3 = \frac{3}{4}(9 + 1)Q

3

=

4

3

(9+1)

Q_3 = \frac{3}{4}*10Q

3

=

4

3

∗10

Q_3 = 7.5th\ itemQ

3

=7.5th item

This means that the Q3 is the mean of the 7th and 8th data.

So:

Q_3 = \frac{1}{2}(12+15)Q

3

=

2

1

(12+15)

Q_3 = \frac{1}{2}*27Q

3

=

2

1

∗27

Q_3 = 13.5Q

3

=13.5

4 0
2 years ago
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