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3 years ago

Which equation represents a line which is parallel to the line y = -3x – 1 ?

Mathematics

1 answer:

Drupady [299]3 years ago

4 0

Answer:3x+y=-8

Step-by-step explanation: If you were to solve each equation by graph the slope would be negative 3

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What is the value of each expression (-3)2

k0ka [10]

First you had to remove parenthesis first.

$-3*2=-6$

Multiply by the numbers.

$3*2=6$

Final answer $\boxed{=-6}$

$6/3=2$

$2*3=6$

$6/2=3$

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

5 0

3 years ago

A container weighs 23 2/5 pounds holds sports equipment. Of the equipment in the container 1/3 of the weight is baseball equipme

hram777 [196]

What we need to know is how much is 1/3 of 25 2/5.

We will be multiplying fraction by a fraction and for this, it's good to change mixed numbers into improper fractions:

25 2/5= $\frac{23*5+2}{5}= \frac{117}{5}$

and now we multiply it by 1/3:

$\frac{1}{3}\frac{117}{5}=\frac{39}{5}=7\frac{4}{5}$

and that's the answer: the basketball equipment weights 7 4/5 pounds.

8 0

3 years ago

1. What is the difference between a median of a triangle and an altitude?

Step2247 [10]

Answer:

The difference between a median and altitude of a triangle is given below :

Altitude is the perpendicular line drawn from a vertex of a triangle to its opposite side .But a median of a triangle is a segment connecting a vertex to the midpoint of its opposite side.

Step-by-step explanation:

The difference between a median and altitude of a triangle is given below :

Altitude is the perpendicular line drawn from a vertex of a triangle to its opposite side .But a median of a triangle is a segment connecting a vertex to the midpoint of its opposite side.

4 0

3 years ago

Please help me out pleaseee

snow_lady [41]

The answer is C.0.2
That’s what I got

3 0

3 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago