3 years ago

Can anyone solve this for me?? I need help ASAP!!

Physics

1 answer:

Pie3 years ago

6 0

Answer:

option A is rightttttttt

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Answer:

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Explanation:

For the launch pad section:

Vf = Vo + a*t where Vo=0.

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The distance traveled during the launch:

$d = Vo*t+\frac{a*t^2}{2} = 0+\frac{35*25^2}{2} = 10937.5m$

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Solving for t:

t1 = -11.093s t2 = 98.59s

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$t_{total} = t_{launch}+t_{projectile}=25+98.59 = 123.59s$

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