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3 years ago

A player uses a hockey stick to push a puck at a constant velocity across the ice. The weight of the puck is 170 N. The

Physics

2 answers:

soldi70 [24.7K]3 years ago

8 0

Answer: The minimum force by which player should hit the puck to move it is 0.102 N.

Explanation:

Weight of the puck = 1.70 N

This weight of the puck is the force acting normal to the surface that is:

N = 1.70 N

The coefficient of friction =

Frictional force =

The minimum force by which player should hit the puck to move it is 0.102 N.

Read more on Brainly.com - brainly.com/question/9177221#readmore

Bingel [31]3 years ago

6 0

Answer:

F=10.2N : Force with which the player must push the disc

Explanation:

Conceptual analysis

We apply Newton's first law because the speed is constant in horizontal direction (x):

∑Fx = 0 Formula (1)

We apply Newton's first law because the speed is zero in vertical direction (y):

∑Fy= 0 Formula (2)

∑F: algebraic sum of forces in Newton (N)

We calculate the friction force with the following formula:

Ff=f*N Formula (3)

Ff= friction force in Newtons (N)

f = coefficient of friction

N= Normal force in Newtons (N)

Known data:

Wp = 170 N : puck weight

f = 0.0600 :coefficient of friction

Problem development

We replace the data in formula (1) and (2), considering that the force is positive (+) if it goes in the direction of the movement and negative (-) if it opposes the movement:

∑Fy= 0

N-Wp=0

N= Wp=170 N

∑Fx =0

F - Ff=0 F :force with which the player must push the disc

F - 0.0600*170 =0

F=10.2N

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Answer:

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The Ranking of the curve according to their speed would be equal Rank because $v_1 =v_2 =v_3$

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For the first frequency we have

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This means that r varies inversely to the angular velocity ,What this means for ranking due to the radius is that the ranking of the second third frequency would be the same but their ranking would be greater than that of the first frequency because

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