Question

A player uses a hockey stick to push a puck at a constant velocity across the ice. The weight of the puck is 170 N. The

Answer 1

Answer: The minimum force by which player should hit the puck to move it is 0.102 N.

Explanation:

Weight of the puck = 1.70 N

This weight of the puck is the force acting normal to the surface that is:

N = 1.70 N

The coefficient of friction =

Frictional force =

The minimum force by which player should hit the puck to move it is 0.102 N.

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Answer 2

Answer:

F=10.2N : Force with which the player must push the disc

Explanation:

Conceptual analysis

We apply Newton's first law because the speed is constant in horizontal direction (x):

∑Fx = 0 Formula (1)

We apply Newton's first law because the speed is zero in vertical direction (y):

∑Fy= 0 Formula (2)

∑F: algebraic sum of forces in Newton (N)  

We calculate the friction force with the following formula:

Ff=f*N  Formula (3)

Ff= friction force in Newtons (N)

f = coefficient of friction

N= Normal force in Newtons (N)

Known data:

Wp = 170 N  : puck weight

f = 0.0600 :coefficient of friction

Problem development

We replace the data in formula (1) and (2), considering that the force is positive (+) if it goes in the direction of the movement and negative (-) if it opposes the movement:

∑Fy= 0

N-Wp=0

N= Wp=170 N

∑Fx =0

F - Ff=0    F :force with which the player must push the disc

F - 0.0600*170 =0

F=10.2N