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Phoenix [80]
2 years ago
9

You need to produce a buffer solution that has a pH of 4.97. You already have a solution that contains 10. mmol (millimoles) of

acetic acid. How many millimoles of acetate (the conjugate base of acetic acid) will you need to add to this solution?
Chemistry
1 answer:
motikmotik2 years ago
5 0

Answer:

16.9 mmoles are needed to add to the solution

Explanation:

To solve this, we can apply the Henderson Hasselbach equation:

Acetic acid → CH₃COOH

CH₃COOH  +  H₂O  ⇄  CH₃COO⁻   +  H₃O⁺             Ka

That is the acid base equilibrium, to determine the amount:

pKa of acetic acid is 4.74

Henderson Hasselbach formula is:

pH = pKa + log (base/acid)

We replace  →  4.97 = 4.74 + log (B / 10mmoles)

Let's verify mmoles of B

4.97 - 4.74 = log (B/10)

0.23 =  log (B/10)

10^(0.23) = 10^(log (B/10)

1.698 = B/10

B = 1.698 . 10 → 16.9 mmoles

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The half-life of tritium (H-3) is 12.3 years. If 48.0mg of tritium is released from a nuclear power plant during the course of a
Amiraneli [1.4K]

Answer:

Explanation:

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3 0
2 years ago
A student weighs out 0. 0422 g of magnesium metal. The magnesium metal is reacted with excess hydrochloric acid to produce hydro
lutik1710 [3]
  • The student weighs out 0.0422 grams of the metal magnesium, thus we can figure that the more's, the magnesium he used, is the mass of the magnesium over the more mass, which is 0.024422.
  • That is approximately 0.001758.
  • Furthermore, it claims that too much hydrochloric acid causes the metal magnesium to react, producing hydrogen gas.
  • The volume of collected gas is 43.9 cc, the mastic pressure is 22 cc, and a sample of hydrogen gas is collected over water in a meter.
<h3>Is it true that calculations made utilizing experimental and gathered data result in a percent error? </h3>
  • Consequently, we are aware that magnesium and chloride react.
  • We create 1 as the reaction ratio is 1:2.
  • The hydrogen and 1 are more.
  • Magnesium chloride is more.
  • Therefore, based on this equation, we can infer that the amount of hydrogen that would be created in this scenario is greater than the amount of magnesium present here, or 0.001758 more.
  • Among hydrogen, there is.
  • \Once we convert the temperature from 32 Celsius to kelvin, we can tell you that the temperature is actually about 5.15 kelvin.
  • The gas has a volume of 43 in m, which is equal to 0.0439 liter and indicates that the pressure is approximately 832 millimeter.
  • Mercury, which is 2 times 13332 plus ca, or roughly 110922.24 par, is a mathematical constant.
  • So, in this instance, we are aware that p v = n r t.
  • The r in this case equals p v over n t, thus we want to determine the r.
  • So p is 110922.24. The temperature is 305.15 and the V is 0.04  over the n is 0.001758.
  • Let's proceed with the calculations right now.
  • In this instance, you will discover that the solution is 9.077 times 10; that is all there is to it.

To learn more about Magnesium chloride reactions visit:

brainly.com/question/27891157

#SPJ4

3 0
2 years ago
A sample of a hydrocarbon is found to contain 7.48g carbon and 2.52g hydrogen. What is the empirical
Aliun [14]

Answer:

CH₄

Explanation:

To determine the empirical formula of the hydrocarbon, we need to follow a series of steps.

Step 1: Determine the mass of the compound

The mass of the compound is equal to the sum of the masses of the elements that form it.

m(CxHy) = mC + mH = 7.48 g + 2.52 g = 10.00 g

Step 2: Calculate the percent by mass of each element

%C = mC / mCxHy × 100% = 7.48 g / 10.00 g × 100% = 74.8%

%H = mH / mCxHy × 100% = 2.52 g / 10.00 g × 100% = 25.2%

Step 3: Divide each percentage by the atomic mass of the element

C: 74.8/12.01 = 6.23

H: 25.2/1.01 = 24.95

Step 4: Divide both numbers by the smallest one, i.e. 6.23

C: 6.23/6.23 = 1

H: 24.95/6.23 ≈ 4

The empirical formula of the hydrocarbon is CH₄.

6 0
3 years ago
Match each statement with one of these terms.
skelet666 [1.2K]

Answer:

1 - e, 2 - k, 3 - a, 4 - i, 5 - b,

Explanation:

The ratio of the amount of analyte in the stationary phase to the amount in the mobile phase. --- Retention factor.

Time it takes after sample injection into the column for the analyte peak to appear as it exits the column. -- Retention time

The process of extracting a component that is adsorbed to a given material by use of an appropriate solvent system. -- Elution

Measure of chromatographic column efficiency. The greater its value, the more efficient the column. -- Theoretical plate number

Gas, liquid, or supercritical fluid used to transport the sample in chromatographic separations. -- Mobile phase

Immiscible and immobile, it is packed within a column or coated on a solid surface. -- Stationary phase

8 0
2 years ago
What mass of agno3 can be dissolved in 250g of water at 20°c?
Mice21 [21]
Hello there,

You should know the <span>solubility of AgNO3 in water at 20°C equals to 2220 g/L.

So we can say that in 1 L of water, 2220 g of AgNO3 can be dissolve.

Now you should know 1L = 1000g.

Which means 1000 g of water can dissolve 2220 g of AgNO3.

Therefore :

</span>250 g<span> --> x
1000 g --> 2220 g

So : </span>x = \frac{250*2220}{1000} =  \frac{555000}{1000}= 555g.

In short, 555g of AgNO3 can be dissolved in 250g of water at 20°C.

Hope this helps !

Photon
4 0
3 years ago
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