Answer:
16.9 mmoles are needed to add to the solution
Explanation:
To solve this, we can apply the Henderson Hasselbach equation:
Acetic acid → CH₃COOH
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
That is the acid base equilibrium, to determine the amount:
pKa of acetic acid is 4.74
Henderson Hasselbach formula is:
pH = pKa + log (base/acid)
We replace → 4.97 = 4.74 + log (B / 10mmoles)
Let's verify mmoles of B
4.97 - 4.74 = log (B/10)
0.23 = log (B/10)
10^(0.23) = 10^(log (B/10)
1.698 = B/10
B = 1.698 . 10 → 16.9 mmoles