Answer:
Most likely Spring or fall
Explanation:
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Answer:
The molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M.HOW TO CALCULATE MOLARITY:The molarity of a solution can be calculated by dividing the number of moles by its volume. That is;Molarity = no. of moles ÷ volumeAccording to this question, 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide. The molarity is calculated as follows:Molarity = 0.50mol ÷ 2LMolarity = 0.25MTherefore, the molarity of 2.0 liters of an aqueous solution that contains 0.50 mol of potassium iodide is 0.25M.Learn more about molarity at: brainly.com/question/2817451
Explanation:
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Answer: The time is 0.69/k seconds
Explanation:
The following integrated first order rate law
ln[SO₂Cl₂] - ln[SO₂Cl₂]₀ = - k×t
where
[SO₂Cl₂] concentration at time t,
[SO₂Cl₂]₀ initial concentration,
k rate constant
Therefore, the time elapsed after a certain concentration variation is given by:
![t=\frac{ln[SO_{2}Cl_{2}]_{0} - ln[SO_{2}Cl_{2}]}{k}=\frac{ln\frac{[SO_{2}Cl_{2}]_{0}}{[SO_{2}Cl_{2}]} }{k}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bln%5BSO_%7B2%7DCl_%7B2%7D%5D_%7B0%7D%20-%20ln%5BSO_%7B2%7DCl_%7B2%7D%5D%7D%7Bk%7D%3D%5Cfrac%7Bln%5Cfrac%7B%5BSO_%7B2%7DCl_%7B2%7D%5D_%7B0%7D%7D%7B%5BSO_%7B2%7DCl_%7B2%7D%5D%7D%20%7D%7Bk%7D)
We could assume that SO₂Cl₂ behaves as a ideal gas mixture so partial pressure is proportional to concentration:

![[SO_{2}Cl_{2}]= \frac{n_{(SO_{2}Cl_{2})}}{V}}=\frac{p_{(SO_{2}Cl_{2})}}{RT}}](https://tex.z-dn.net/?f=%5BSO_%7B2%7DCl_%7B2%7D%5D%3D%20%5Cfrac%7Bn_%7B%28SO_%7B2%7DCl_%7B2%7D%29%7D%7D%7BV%7D%7D%3D%5Cfrac%7Bp_%7B%28SO_%7B2%7DCl_%7B2%7D%29%7D%7D%7BRT%7D%7D)
In conclusion,
t = ln( p(SO₂Cl₂)₀/p(SO₂Cl₂) )/k

for





C: condensation
Examples are glasses fogging up and water droplets on a can of soda when it’s hot
<span>Answer:
2Al(s) + 3Cl2(g) ---> 2AlCl3(s)
Always work in moles
moles = mass of substane / molar mass
2Al (s) + 3Cl (g) --> 2AlCl3 (s)
moles Al = 23.0 g / 26.98 g/mol
= 0.852 moles Al</span>