It depends on what type of graph you have. The easiest would be using a H-T diagram. Enthalpy of vaporization is the physical change from liquid to vapor. It occurs at a constant pressure and a constant temperature. As shown in the picture, 1 point is drawn on the subcooled liquid, and another point of the saturated vapor isothermal line. Now, the difference between those two points is the value for the enthalpy of vaporization of water.
<em><u>look at the clues by it and try not to trust the links they trying to give u...</u></em>
<em><u>but i kinda dont know myself any periodic table i can look at?</u></em>
<span>Since these molecules are all non-polar, the only intermolecular force of attraction will be London dispersion forces. Since these increase by the size of the molecule, the boiling points will decrease in the same order:
Parafin > Heptadecane > hexane > 2,2-dimethylbutane > propane
For these two, hexane > 2,2-dimethylbutane, dispersion forces are greater in a molecule which is longer and unbranched compared to one which is branched and more compact.</span>
Answer:
A) ψ² describes the probability of finding an electron in space.
Explanation:
The Austrian physicist Erwin Schrödinger formulated an equation that describes the behavior and energies of submicroscopic particles in general.
The Schrödinger equation i<u>ncorporates both particle behavior</u>, in terms of <u>mass m</u>, and wave behavior, in terms of a <u><em>wave function ψ</em></u>, which depends on the location in space of the system (such as an electron in an atom).
The probability of finding the electron in a certain region in space is proportional to the square of the wave function, ψ². According to wave theory, the intensity of light is proportional to the square of the amplitude of the wave, or ψ². <u>The most likely place to find a photon is</u> where the intensity is greatest, that is, <u>where the value of ψ² is greatest</u>. A similar argument associates ψ² with the likelihood of finding an electron in regions surrounding the nucleus.
Mg(NO3)2 ➡️ Mg2+ + 2 NO3-
(32.0g Mg(NO3)2) / (148.3g Mg(NO3)2/mol)* (2 mol NO3- / 1 mol Mg(NO3)2) / (0.425 L) = 1.02 mol/ L NO3-