Answer:
Explanation:
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In this case, the combustion of octane is chemically expressed by:
In such a way, due to the 25/2:8 molar ratio between oxygen and carbon dioxide, we can compute the yielded grams of carbon dioxide (molar mass 44 g/mol) as shown below:
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The gas sample consists of CH₄ and He.
Number of CH₄ moles - 4 g/ 16 g/mol = 0.25 mol
molar volume is where 1 mol of any gas occupies a volume of 22.4 L
Therefore 0.25 mol of CH₄ gas occupies a volume of 22.4 L/mol x 0.25 mol
Volume of methane - 5.6 L
Number of He moles - 2.00 g/ 4 g/mol = 0.5 mol
Volume occupied by He - 22.4 L /mol x 0.5 mol = 11.2 L
The total volume of the sample = 5.6 L + 11.2 L = 16.8 L
This family (ethane, propane, butane, etc) of materials is likely to have following set of properties.
- The alkanes are non- polar solvents.
- The alkanes are immiscible in water but freely miscible in other non-polar solvent .
- The alkanes are consisting of weak dipole dipole bonds can not breaks the strong hydrogen bond.
- The alkanes having only carbon (C) and hydrogen (H) atom which is bonded by a single bonds only.
- The alkanes posses weak force of attraction that is weak van der waals force of attraction.
The ethane, propane, butane, belong to alkanes family.The alkanes are also considers as saturated hudrocarbons. Ethane is found in gaseous stae Ethane is the second alkane followed by propane followed by butane.
learn about butane
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D is the correct answer.
The trend that follows a group (vertical lines) is that they each contain the same number of valence (outer) electrons
Answer:
Boiling point.
Explanation:
Flammability, reactivity and toxicity are all chemical properties!
