2 CH₃CH₂CH₃ + 2 Cl₂ → CH₃CH(Cl)CH₃ + CH₃CH₂CH₂Cl + 2 HCl
so according to balanced equation we notice that:
2 mole of propane reacts with 2 moles of Cl₂, so 6 moles of propane will need to react completely with 6 moles Cl₂ (This mean Cl₂ present in excess and propane is the Limiting reagent)
2 mole C₃H₈ gives 2 moles HCl
6 moles C₃H₈ gives ? moles HCl
by cross multiplication we have 6 moles of HCl formed
when Kc = [the concentration of products]^(no.of its mol in the balanced equation) / [the concentration of the reactants]^(no.of mol in the balanced equation)
∴ The equilibrium constant expression for this reaction is:
Kc= [H+]^2 * [So4-2] / [H2SO4]
Answer: hope this helps
To make molar NaCl solutions of other concentrations dilute the mass of salt to 1000ml of solution as follows:
0.1M NaCl solution requires 0.1 x 58.44 g of NaCl = 5.844g.
0.5M NaCl solution requires 0.5 x 58.44 g of NaCl = 29.22g.
2M NaCl solution requires 2.0 x 58.44 g of NaCl = 116.88g.
Explanation:
Answer:
A Beaker, however if you are doing this from home a measuring cup would probably be more available.
