The chemical reaction is expressed as:
<span> 4KO2+2CO2→2K2CO3+3O2
</span>
We are given the amount of KO2 to be used in the reaction. This will be the starting point of our calculations. We do as follows:
0.425 mol KO2 ( 3 mol O2 / 4 mol KO2 ) = 0.319 mol O2 produced
Hope this answers the question. Have a nice day.
% error =

x 100%
Experimental: 2.85
Actual (theoretical): 2.70
% error =

x 100% = .055555 x 100% = 5.56%
Lithium Arsenate - Li3AsO4 (160g/mol). So, it’s 2,13 mol * 160 g/mol = 340,8 g.
The answer would be D carbon dioxide