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artcher [175]
3 years ago
10

What is the percent of O in CO2

Chemistry
2 answers:
zmey [24]3 years ago
5 0

72.71 . simple google search, you shouldnt waste points

MrMuchimi3 years ago
4 0

For this case we have the CO_ {2}

It is composed of one atom of carbon and two of oxygen.

The atomic mass of carbon and oxygen, which can be found in a periodic table, are given by:

C: 12 \frac {g} {mol}\\O: 16 \frac {g} {mol}

Then, we find the atomic mass of CO_{2}:

1 * 12 \frac {g} {mol} = 12 \frac {g} {mol}\\2 * 16 \frac {g} {mol} = 32 \frac {g} {mol}

Adding we have:

44 \frac {g} {mol}

To find the percentage of oxygen, we divide the atomic mass of the two oxygen atoms between that of CO_{2}:

\frac {32} {44} * 100 = 72.73%

Thus, the percentage of oxygen is 72.73%

Answer:

72.73%

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3 years ago
What evidence do you have that tpgs-750m increases the reaction rate? How does tpgs-750m act to increase the reaction rate?
notka56 [123]

TPGS-750 M conducts reaction under lower temperature then the reactions carried out in organic solvents.

<h3>What is tpgs-750m ?</h3>

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7 0
1 year ago
Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that
iragen [17]

Answer:

108.43 grams KNO₃

Explanation:

To solve this problem we use the formula:

  • ΔT = Kf * b * i

Where

  • ΔT is the temperature difference (14.5 K)
  • Kf is the cryoscopic constant (1.86 K·m⁻¹)
  • b is the molality of the solution (moles KNO₃ per kg of water)
  • and<em> i</em> is the van't Hoff factor (2 for KNO₃)

We <u>solve for b</u>:

  • 14.5 K = 1.86 K·m⁻¹ * b * 2
  • b = 3.90 m

Using the given volume of water and its density (aprx. 1 g/mL) we <u>calculate the necessary moles of KNO₃</u>:

  • 275 mL water ≅ 275 g water
  • 275 g /1000 = 0.275 kg
  • moles KNO₃ = molality * kg water = 3.90 * 0.275
  • moles KNO₃ = 1.0725 moles KNO₃

Finally we <u>convert KNO₃ moles to grams</u>, using its molecular weight:

  • 1.0725 moles KNO₃ * 101.103 g/mol = 108.43 grams KNO₃
5 0
3 years ago
A compound contains 34.5% calcium, 24.1% silicon and 41.4% oxygen by mass. What is its empirical formula?
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<em>empirical \: formula \\  = CaSiO3 \\ please \: see \: the \: attached \: picture \\ hope \: it \: helps</em>

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