Answer:
The answer to your question is: 65.9 g released of CO2
Explanation:
MW CO2 = 44 g
MW CuCO3 = 123.5 g
CO2 released = ?
CuCO3 = 185 g
CuCO3 ⇒ CO2 + CuO
123.5 ----------- 44g
185 g ----------- x
x = (185 x 44) / 123.5
x = 65.9 g released of CO2
Answer:
I have solved your problem
Explanation:
Hey there!
<span>Atomic Masses :
</span>
H = <span>1.00794 a.m.u
N = </span><span>14.0067 a.m.u
O = </span><span>15.9994 a.m.u
Therefore:
HNO3 = </span>1.00794 + 14.0067 + ( 15.9994 * 3 ) => <span>63.0128 g/mol</span>
Answer:
Benzene must be kept away from flames.
Explanation:
Edge2020
C seems to be the best answer