100 times less H+
A solution at ph 10 contains<u> </u><u>100 times less H+</u> than the same amount of solution at ph 8.
<h3>The pH scale: How does it function?</h3>
- The pH scale determines how acidic or basic water is.
- The range is 0 to 14, with 7 representing neutrality.
- Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7.
- In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.
<h3>How does the pH change when two acids are combined?</h3>
- An acid's strength increases with the quantity of hydrogen ions it releases.
- The pH of the strong acids is between 1 and 2.
- We may observe that there is no response when two acids of the same strength are combined.
- It's because the end product will be neutral and the pH won't change.
<h3>How is pH value determined?</h3>
There are two ways to measure pH:
- colorimetrically with indicator fluids or sheets
- electrochemically with electrodes and a millivoltmeter for greater accuracy (pH meter).
To learn more about pH visit:
brainly.com/question/491373
#SPJ4
Answer:
Explanation:
- For the balanced reaction:
<em>4Fe(s) + 3O₂(g) → 2Fe₂O₃(s).</em>
It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.
- Firstly, we need to calculate the no. of moles of 35.8 grams of Fe metal:
no. of moles of Fe = mass/molar mass = (35.8 g)/(55.845 g/mol) = 0.64 mol.
- Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:
<em><u>Using cross multiplication:</u></em>
4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.
0.64 mol of Fe is needed to react with → ??? mol of O₂.
∴ The no. of moles of O₂ needed = (3 mol)(0.64 mol)/(4 mol) = 0.48 mol.
- Finally, we can get the volume of oxygen using the information:
<em>It is known that 1 mole of any gas occupies 22.4 L at standard P and T (STP).</em>
<em></em>
<em><u>Using cross multiplication:</u></em>
1 mol of O₂ occupies → 22.4 L, at STP conditions.
0.48 mol of O₂ occupies → ??? L.
∴ The no. of liters of O₂ = (0.48 mol)(22.4 L)/(1 mol) = 10.752 L.
NaCl (Sodium chloride)
LiF (Lithium fluoride)
Answer:
To answer your question use the code ICE on here to get your answer works every time for me hope this helps