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3 years ago

What is the physical state of the smallest alkanes at room temperature?

Chemistry

1 answer:

dem82 [27]3 years ago

8 0

They are gases at room temperature

Hope this helps:)

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Compare and contrast all the periodic trends as you move down a group of metais. Organize

elena55 [62]

Answer:

The number of energy levels increases as you move down a group as the number of electrons increases. Each subsequent energy level is further from the nucleus than the last. Therefore, the atomic radius increases as the group and energy levels increase.

Explanation:

Dose this help? Tell me if it dose.

4 0

3 years ago

Read 2 more answers

Why is it that the shoreline tends to have milder temperatures in the winter than mainland?

Volgvan

I think its becuse the shoreline is shalow water that is warmed by the sun? ...... I may be rong

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3 years ago

A gas evolved during the fermentation of alcohol had a volume of 19.4 L at 17 °C and 746 mmHg. How many moles of gas were collec

AlexFokin [52]

Answer:- 0.800 moles of the gas were collected.

Solution:- Volume, temperature and pressure is given for the gas and asks to calculate the moles of the gas.

It is an ideal gas law based problem. Ideal gas law equation is used to solve this. The equation is:

PV=nRT

Since it asks to calculate the moles that is n, so let's rearrange this for n:

$n=\frac{PV}{RT}$

V = 19.4 L

T = 17 + 273 = 290 K

P = 746 mmHg

we need to convert the pressure from mmHg to atm and for this we divide by 760 since, 1 atm = 760 mmHg

$P=746mmHg(\frac{1atm}{760mmHg})$

P = 0.982 atm

R = $0.0821\frac{atm.L}{mol.K}$

Let's plug in the values in the equation to get the moles.

$n=\frac{0.982atm*19.4L}{0.0821\frac{atm.L}{mol.K}*290K}$

n = 0.800 moles

So, 0.800 moles of the gas were collected.

4 0

3 years ago

Please someone answer and help :)

algol [13]

13. D
14. A
15. C
16. B
17. F
18. E

7 0

3 years ago

A chemist must dilute of aqueous aluminum chloride solution until the concentration falls to . He'll do this by adding distilled

marshall27 [118]

Answer:

0.257 L

Explanation:

The values missing in the question has been assumed with common sense so that the concept could be applied

Initial volume of the AICI3 solution $=23.1 \mathrm{mL}$

Initial Molarity of the solution $=833 \mathrm{mM}$

Final molarity of the solution $=75.0 \mathrm{mM}$

Final volume of the solution $=?$

From Law of Dilution, $M_{f} V_{f}=M_{i} V_{i}$

$\Rightarrow V_{f}=\frac{M_{i} V_{i}}{M_{f}}=\frac{833 \mathrm{mM} \times 23.1 \mathrm{mL}}{75.0 \mathrm{mM}}=256.564 \mathrm{mL}=0.256564 \mathrm{L}=0.257 L$

Final Volume of the solution $=0.257$

7 0

3 years ago