Answer:
All of these are just different "intensities" of radiation and in a manner, different intensities of light.
Explanation:
Note that all of these are just different "intensities" of radiation and in a manner, different intensities of light. So, they differ only on the amount of energy they have or imparts. Note that light travels in a wavelike manner.
The higher the intensity, the shorter the wavelength and the higher the energy. This goes in opposite to radiation with longer wavelength in which it has lower intensity and energy.
Explanation:
Answer:
Explanation:
Hydroponics is the process of growing crops using only water and liquid fertilizer. This process is great when your in the big city.
It is observed that when magnesium reacts with hydrochloric acid, it produces visible bubbles of hydrogen gas.
A vigorous reaction will occur giving rise of heat as it is an exothermic reaction. If heat is applied then it should be more vigorous.
Reaction is as follows:
Mg(s) + HCl (aq) --> MgCl2 (aq) + H2(g)
Magnesium reacts easily with HCl to produce H2 gas and magnesium ions, Mg2+, and heat. The reaction is exothermic, so it heats up quickly.
Mg(s) + HCl (aq) --> MgCl2(aq) + H2(g)
The net ionic equation :
Mg(s) + 2H+ --> Mg2 + H2(g)
If water is removed from the solution then white crystals of Mgcl2 is obtained.
Or in simple words,
2Mg + 2HCl -> 2Mg+ + 2Cl- + H2(gas)
The magnesium is attacked by the hydrochloric acid resulting in the magnesium dissolving into the solution resulting in a solution of magnesium chloride in hydrochloric acid and the production of hydrogen gas.
Learn more about magnesium here : brainly.com/question/5759562
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A). The weaker the IMF the lower the evaporation rates of each liquid. So Pentane had the weakest IMF and Butanol has the strongest.
b).They all evaporate at different rates because of their differences in their bonds. Not all liquids are the same and they will all most likely evaporate at different times
Answer:
hello your question is incomplete attached below is the complete question
Pyridinium ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH and after the reaction it comes out neutral.
N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while
B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion
Explanation:
Pyridine ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH and after the reaction it comes out neutral.
N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while
B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion
attached below is the remaining part of the solution
