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NNADVOKAT [17]
2 years ago
14

WILL GIVE BRAINLIEST Pam and Caroline determined the mass and volume of a piece of metal to be 34.16 g and 11.3 mL respectively.

Determine the density of the metal. (Please show work and use significant figures.
Chemistry
1 answer:
dlinn [17]2 years ago
6 0

Answer:

0.303kg/m

Explanation:

Density=m/v where m is mass

and v is volume

we then convert m in grams to kg

= 34.16/1000

=0.0342kg

converting ml to m

=11.3/100

=0.113m

then density=0.0342/0.113

=0.303kg/m

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Charles law gives the relationship between volume and temperature of gas.
It states that at constant pressure volume is directly proportional to temperature
Therefore
V/ T = k
Where V - volume T - temperature in kelvin and k - constant
V1/T1 = V2/T2
Parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
Substituting the values in the equation
267 L/ 480 K = V / 750 K
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Final volume is 417 L
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3 years ago
Density of a piece of wood that has a measurement of 24 cm3 and 768 g
Brut [27]

Answer:

<h3>The answer is 32 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 768 g

volume = 24 cm³

We have

density =  \frac{768}{24}  \\

We have the final answer as

<h3>32 g/cm³</h3>

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When iron metal reacts with oxygen, the reaction can form Fe2O3. Write a balanced chemical equation for this reaction, and find
I am Lyosha [343]
<h3>Answer:</h3>

Balanced equation: 4Fe + 3O₂ → 2Fe₂O₃

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<h3>Explanation:</h3>

To answer the question;

  • We first write the balanced equation between iron metal and Oxygen
  • The balanced equation is given as;

4Fe + 3O₂ → 2Fe₂O₃

  • We are given 6 moles of Fe₂O₃

We are required to determine the number of moles of oxygen needed to form 6 moles of Fe₂O₃.

  • From the equation, 3 moles of oxygen gas reacts to produce 2 moles of Fe₂O₃
  • This means, the mole ratio of O₂ to Fe₂O₃ is 3 : 2

Therefore; Moles of O₂ = Moles of Fe₂O₃ × 3/2

Hence, moles of oxygen = 6 moles × 3/2

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Thus, Moles of Oxygen needed is 9 moles

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