The velocity and acceleration of the particle moving round the circle is;
<em><u>Velocity = 162.12 m/s</u></em>
<em><u>Velocity = 162.12 m/sAcceleration = 6.873 × 10^(-5) m/s²</u></em>
We are given;
Radius of circle; 382400 km = 382400000 m
Time; t = 27.3 days = 27.3 × 86400 s = 2358720 s
Now, formula for velocity is;
Velocity = distance/time
Thus;
I) velocity = 382400000/2358720
Velocity = 162.12 m/s
II) Acceleration is centripetal acceleration and is given by the formula;
a = v²/r
a = 162.12²/382400000
a = 6.873 × 10^(-5) m/s²
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Answer:
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Answer:
90,000 J
Explanation:
Kinetic energy can be found using the following formula.

where <em>m </em>is the mass in kilograms and <em>v</em> is the velocity in m/s.
We know the object has a mass of 50 kilograms. We also know it is a traveling at a rate of 60 m/s. Velocity is the speed of something, so the velocity of the object is 60 m/s.
<em>m</em>=50
<em>v</em>=60
Substitute these values into the formula.

First, evaluate the exponent: 60^2. 60^2 is the same as multiplying 60, 2 times.
60^2=60*60=3,600

Multiply 50 and 3,600

Multiply 1/2 and 3,600, or divide 3,600 by 2.

Add appropriate units. Kinetic energy uses Joules, or J.

The kinetic energy of the object is 90,000 Joules
Answer:

Explanation:
given,
side slope = 1 : 1
hydraulic depth(y) = 5 ft
bottom width (b)= 8 ft
x = 1
Q = 2,312 ft³/s
n = 0.013
slope of channel = ?



R = 4.69 m
using manning's equation



S = 0.406
