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amm1812
2 years ago
7

Can someone help me name the layers.

Physics
2 answers:
BARSIC [14]2 years ago
7 0

Answer:

A. Crust

B. Mantle

C. Outer Core

D. Inner Core

Explanation:

Nadya [2.5K]2 years ago
4 0

Answer:

A. Crust

B. mantle

C. outer core

D. inner core

Explanation:

because it is

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In your research lab, a very thin, flat piece of glass with refractive index 1.50 and uniform thickness covers the opening of a
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The longest wavelength in vacuum for which there is constructive interference for the reflected light, λ   = 3472.

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Refractive index of Glass (given) = 1.5

For the case of a constructive interference,

2nt = (m + 1/2) λ

For case 1,

2nt = (m + 1/2) 496 nm

For case 2,

2nt = (m +1+ 1/2) 386 nm

2nt = (m+3/2) * 386 nm

(m + 1/2) 496 nm = (m+3/2) * 386 nm

m = 3

Inserting the value of m in 1.

2nt = (m + 1/2) 496 nm

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t = ((3 + 1/2) * 496 nm)/ 3

t = 578.6 nm

The thickness of the glass, t = 578.6 nm

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It is generally known that for constructive interference,

2nt = (m + 1/2) λ

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λ = 3472 nm

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2 years ago
A proton traveling due west in a region that contains only a magnetic field experiences a vertically upward force (away from the
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A 100 N force is applied to a 50 kg crate resting on a level floor. The coefficient of kinetic friction is 0.15. What is the acc
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The acceleration of the crate after it begins to move is 0.5 m/s²

We'll begin by calculating the the frictional force

Mass (m) = 50 Kg

Coefficient of kinetic friction (μ) = 0.15

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) = mg = 50 × 10 = 500 N

<h3>Frictional force (Fբ) =?</h3>

Fբ = μN

Fբ = 0.15 × 500

<h3>Fբ = 75 N</h3>

  • Next, we shall determine the net force acting on the crate

Frictional force (Fբ) = 75 N

Force (F) = 100 N

<h3>Net force (Fₙ) =?</h3>

Fₙ = F – Fբ

Fₙ = 100 – 75

<h3>Fₙ = 25 N</h3>

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Mass (m) = 50 Kg

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<span>The acceleration of the bullet is called ACTION.

</span>Formally stated, Newton's third law<span> is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.
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