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Novay_Z [31]
3 years ago
10

On the earth, when an astronaut throws a 0.250-kg stone vertically upward, it returns to his hand a time T later. On planet X he

finds that, under the same circumstances, the stone returns to his hand in 2T. In both cases, he throws the stone with the same initial velocity and it feels negligible air resistance. The acceleration due to gravity on planet X (in terms of g) is _______.a) g/. b) g/4. c) 2g. d) g/2. e) g.
Physics
1 answer:
Liula [17]3 years ago
4 0

Answer:

correct is d) a ’= g / 2

Explanation:

For this exercise let's use the kinematics equations

On earth

      v = v₀ - a t

     a = (v₀- v) / T

On planet X

    v = v₀ - a' t’

    a ’= (v₀-v) / 2T

Let's substitute the land values ​​in plot X

     a’= a / 2

Now let's use Newton's second law

       W = ma

      m g = m a

      a = g

We substitute

      a ’= g / 2

So we see that on planet X the acceleration is half the acceleration of Earth's gravity

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6 0
4 years ago
A galvanometer with a resistance of 40.0 ω deflects full scale at a current of 2.0 ma. what resistance should be used with this
kogti [31]
The resistance needed to be added is R
The Current is 2 ma
The voltage reading is a maximum of 50 volts.
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Formula
E = I * R

Givens
E = 50
I = 2 ms
R = R + 40

Solution
E = I * R
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8 0
4 years ago
Read 2 more answers
8.
svetoff [14.1K]

Answer:

9.5 seconds

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You need to make the ending speed into meters per sec.

So it would be 120km/h = 33.33m/s

If the acceleration rate is 3.5m/s, then the final answer would equal to 9.5 seconds

Also btw rounding it up is a good idea too so 10 seconds if you round

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