Power rules for both quotient and product sums are useful to simplify large exponential form (of the same base)
The difference is in the rule. For quotient sum, the powers are subtracted, while for product sum, the powers are added up.
An example for quotient sum

Using the principle of simplifying fractions, we can cancel out ten 7s from both numerator and denominator, leaving us with only three 7s on the numerator which gives us

. This working out could be simplified by doing

An example for product sum

. There is a total of eleven 9s if we were to work out the product sum the long way. This could be simplified by doing
Answer:
Rotation
Step-by-step explanation:
If that is an option
Answer:
1
Use the quadratic formula
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
2
+
5
−
2
=
0
x^{2}+5x-2=0
x2+5x−2=0
=
1
a={\color{#c92786}{1}}
a=1
=
5
b={\color{#e8710a}{5}}
b=5
=
−
2
c={\color{#129eaf}{-2}}
c=−2
=
−
5
±
5
2
−
4
⋅
1
(
−
2
)
√
2
⋅
1
Step-by-step explanation:
this should help
To solve for x, first you need to isolate all x terms on the same side so:
you start with 5 + 4x = 54 - 3x
subtract 5 from both sides to get 5 onto the left side
now you should have 4x = 49 - 3x
now add 3x to both sides to get 3x onto the right side
now you should have 7x = 49
now that you have your x on one side you can solve this like a regular one step equation and divide both sides by 7
this leads you to your answer of x = 7
hope this helps!
Answer: Required expression:
Result: 
Step-by-step explanation:
Given phrase: 
Required expression:
['+' used to express sum, 'x' used in place of 'of']
Since 18+16 = 34
Then,
![\dfrac14\times(18+16)=\dfrac14\times34 \\\\=\dfrac{1}{2}\times17\ \ \text{[Divide numerator and denominator by 2]}\\\\=\dfrac{17}{2}](https://tex.z-dn.net/?f=%5Cdfrac14%5Ctimes%2818%2B16%29%3D%5Cdfrac14%5Ctimes34%20%20%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes17%5C%20%5C%20%5Ctext%7B%5BDivide%20numerator%20and%20denominator%20by%202%5D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B17%7D%7B2%7D)
Hence,