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Aleksandr [31]
3 years ago
13

When water reaches the metastable state, the phase of water will be?​

Chemistry
1 answer:
Jet001 [13]3 years ago
7 0

Answer:

water, when the metastable state is reached, is cooled below the zero temperature. It freezes abruptly. this is called metastable. They are not at equilibrium per se; as at negative temperatures the only equilibrium state of water is ice.

Explanation:

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Sulfur dioxide, SO 2 ( g ) , can react with oxygen to produce sulfur trioxide, SO 3 ( g ) , by the reaction 2 SO 2 ( g ) + O 2 (
aleksley [76]

<u>Answer:</u> The amount of heat produced by the reaction is -21.36 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]

For the given chemical reaction:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(SO_3(g))})]-[(2\times \Delta H_f_{(SO_2(g))})+(1\times \Delta H_f_{(O_2(g))})]

We are given:

\Delta H_f_{(SO_2(g))}=-296.8kJ/mol\\\Delta H_f_{(SO_3(g))}=-395.7kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(2\times (-395.7))]-[(2\times (-296.8))+(1\times (0))]\\\\\Delta H_{rxn}=-197.8kJ/mol

To calculate the number of moles, we use ideal gas equation, which is:

PV=nRT

where,

P = pressure of the gas = 1.00 bar

V = Volume of the gas = 2.67 L

n = number of moles of gas = ?

R = Gas constant = 0.0831\text{ L. bar }mol^{-1}K^{-1}

T = temperature of the mixture = 25^oC=[25+273]K=298K

Putting values in above equation, we get:

1.00bar\times 2.67L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1\times 2.67}{0.0831\times 298}=0.108mol

To calculate the heat released of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = ?

n = number of moles = 0.108 moles

\Delta H_{rxn} = enthalpy change of the reaction = -197.8 kJ/mol

Putting values in above equation, we get:

-197.8kJ/mol=\frac{q}{0.108mol}\\\\q=(-197.8kJ/mol\times 0.108mol)=-21.36kJ

Hence, the amount of heat produced by the reaction is -21.36 kJ

3 0
3 years ago
You make 1 Liter of an aqueous solution containing 9.20 ml of 57.8 mM acetic acid and 56.2 mg of sodium acetate (MW = 82.0 g/mol
Whitepunk [10]

Answer:

a) 5,3176x10⁻⁴ moles

b) 6,85x10⁻⁴ moles

c) The appropriate formula to calculate is Henderson-Hasselbalch.

d) pH = 4,86. Acidic solution but slighty

Explanation:

a) moles of acetic acid:

9,20x10⁻³L × 57,8x10⁻³M = <em>5,3176x10⁻⁴ moles</em>

<em></em>

b) moles of sodium acetate:

56,2x10⁻³g ÷ 82,0 g/mole = <em>6,85x10⁻⁴ moles</em>

<em></em>

c) The appropriate formula to calculate is Henderson-Hasselbalch:

pH= pka + log₁₀ \frac{[A^-]}{[HA]}

d) pH= 4,75 + log₁₀ \frac{[6,85x10_{-4}]}{[5,3176x10_{-4}]}

<em>pH = 4,86</em>

<em>3 < pH < 7→ Acidic solution but slighty</em>

I hope it helps!

3 0
4 years ago
What is the heaviest gas there is
Alex
Radon is the heaviest gas on Earth with a density of about 9.73 g/L. This is very high actually. 
For more informations, radon is mostly used in radioactivity and cancer therapy.

Hope this Helps :)
6 0
3 years ago
Read 2 more answers
In terms of d1 and d2, how could you define the bonding atomic radius of atom x?
balu736 [363]
When a covalent bond<span> is present between two </span>atoms<span>, the </span>covalent radius<span> can be determined. When two </span>atoms<span> of the same </span>element<span> are covalently </span>bonded<span>, the </span>radius<span> of each </span>atom<span> will be half the distance between the two nuclei because they equally attract the electrons.</span>
7 0
3 years ago
A fish has armored plates that enable it to handle the extreme pressure in the deepest, darkest aquatic ecosystem.
love history [14]

Answer:

the open ocean

Explanation:

just took the test

6 0
4 years ago
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