3 years ago

(b) the absolute temperature of the gas at which 3.33x103 mol occupies 478 mL at 750 torr,

Chemistry

1 answer:

bija089 [108]3 years ago

6 0

Explanation:

T=?

Given

n=3.33×10³

V=478mL=4.78L

P=750torr= 0.987 Atm

simply use the formula

PV =nRT

where R is universal gas constant

0.987×4.78= 3.33×10³×8.314×T

T = 0.000170°c

T= 273.15 K!

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(b) the absolute temperature of the gas at which 3.33x103 mol occupies 478 mL at 750 torr,​

(b) the absolute temperature of the gas at which 3.33x103 mol occupies 478 mL at 750 torr,