Answer:
feyyeyeuueuehehheueueieuhegebrbjrirororkoeorororproororororri9r
Explanation:
eejjeididodjdjrirr
It's examples are:
1)London dispersion forces
2)Dipole-Dipole forces
3)Hydrogen bonding...
Answer:
+125.4 KJmol-1
Explanation:
∆H C4H10(g) = -2877.6kJ/mol
∆H C(s)=-393.5kJ/mol
∆H H2(g) = -285.8
∆H reaction= ∆Hproducts - ∆H reactants
∆H reaction= (-2877.6kJ/mol) - [4(-393.5kJ/mol) +5(-285.8)]
∆H reaction= +125.4 KJmol-1
There would be a 2 infront of the NH3 and and 2 Infront of the H2O
There are 14 atoms, the 2 at the front times' everything by 2, so there 4Ks, 2Ss and 8Os, altogether 14
