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oksian1 [2.3K]
3 years ago
7

(b) the absolute temperature of the gas at which 3.33x103 mol occupies 478 mL at 750 torr,​

Chemistry
1 answer:
bija089 [108]3 years ago
6 0

Explanation:

T=?

Given

n=3.33×10³

V=478mL=4.78L

P=750torr= 0.987 Atm

simply use the formula

PV =nRT

where R is universal gas constant

0.987×4.78= 3.33×10³×8.314×T

T = 0.000170°c

T= 273.15 K!

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Answer:

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Explanation:

Based on the reaction:

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4 moles of ammonia reacts with 5 moles of oxygen to produces 4 moles of NO and 6 moles of water.

To find limiting reactant we need to find the moles of each reactant and using the balanced equation find which reactant will be ended first. Then, with limiting reactant we can find the moles of each reactant and its mass:

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1.47mol NO * (30.01g/mol) = 44g of NO

c. Moles H2O:

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Mass H2O -Molar mass: 18.01g/mol-

2.205mol H2O * (18.01g/mol) = 40g of H2O

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3 years ago
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<em>Answer:</em>

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