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yuradex [85]
3 years ago
14

How to make a sugar cube dissolve more quickly in water?

Chemistry
1 answer:
Vesna [10]3 years ago
3 0
Heat the water up a little
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How many grams of dextrose are needed to make 725 mL of a 26.0% (w/v) dextrose solution? Note that mass is not technically the s
Diano4ka-milaya [45]

Answer:

188.5g of dextrose are needed

Explanation:

In Weight per volume percentage - %(w/v) -, the concentration is defined as the mass of solute in grams -In this case, dextrose-, in 100mL of solution.

As you want to prepare 725mL of a 26.0% (w/v) solution. you need:

725mL * (26g / 100mL) = 188.5g of solute =

<h3>188.5g of dextrose are needed</h3>
3 0
3 years ago
What is meant by the statement "energy is quantized"?
Sveta_85 [38]

That means that the amount of energy can only be certain numbers, as if
energy came in tiny packets, and the in-between amounts don't exist.

Another example of a measurement in nature that is quantized is
electric charge.


5 0
3 years ago
1. How many moles of iron is needed to react with sulfur in order to produce 8.6 moles
AleksAgata [21]

Answer:

17.2 moles of Iron are required

Explanation:

Based on the chemical reaction:

2Fe + 3S → Fe₂S₃

<em>2 moles of Fe react with 3 moles of S to produce 1 mole of Iron (III) sulfide</em>

<em />

Assuming and excess of sulfur, if we want to obtain 8.6 moles of Fe₂S₃ are required:

8.6 moles Fe₂S₃ * (2 moles Fe / 1mol Fe₂S₃) =

<h3>17.2 moles of Iron are required</h3>
7 0
3 years ago
Moles to mass<br> HELP PLEASE <br> 15 pts
MariettaO [177]

Explanation:

nose amigo, la verdad yo también tengo dificultades escolares muchísimas gracias, Dios te bendiga en otro idioma por cierto mi anime favorito es cowboy beboop

4 0
2 years ago
Calculate the percentage by mass of chlorine in Cobalt (II) chloride (cocl2)​
Likurg_2 [28]

Explanation:

Divide the mass of chlorine by the molar mass of cobalt chloride, then multiply by 100.

Molar Mass of Cobalt Chloride.

Mass of Chlorine in Cobalt Chloride.

Percent Composition of Chlorine.

8 0
3 years ago
Read 2 more answers
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