Question

In right triangle ABC with right angle C, sin A = 4/5 and cos A = 3/5. What is sin B + cos B?

Answer 1

Answer:

so sin B + cos B =

$\frac{7}{5} \: \: or \: \: 1.4$

Step-by-step explanation:

in the given right angled triangle angle A and angle B are complementary to each other

so, Sin A = Cos B

and Cos A = Sin B

now,

=》

$\sin(b) + \cos(b)$

=》

$\cos(a) + \sin(a)$

=》

$\frac{3}{5} + \frac{4}{5}$

=》

$\frac{7}{5}$