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3 years ago

WILL MARK BRAINLIEST!! Given ΔABC : ΔDEF, find x. 10 14 27 12

Mathematics

2 answers:

lilavasa [31]3 years ago

7 0

Answer:

x=12

Step-by-step explanation:

If the triangles are similar:

x/8=18/12

x/8=1.5

x=12

dedylja [7]3 years ago

6 0

Answer:

X=14

Step-by-step explanation:

If you measure them, they'll be very close to the same length.

Also, the triangles are very similar. Given this information, a simple way to solve it is:

12-4=8 so to find X subtract 4 from 18.

18-4=14 so X=14

I hope my brain did the correct math for you.

It probably didn't, but I tried.

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Answer:

If you could please write it down i will solve it for you.

Step-by-step explanation:

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3 years ago

After writing an equation for each of the T-shirt companies, Jill wrote this equation: 30 + 6x = 20 + 8x Why do you think she wr

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Answer:

Step-by-step explanation:

she wrote it to solve the total amount spent on both T shirt.

30+6x=20+8x-8x

30+6x-8x=20

30-30-2x=20

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-2x/-2=-10/-2

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2 years ago

I need help pls answer right and don't just pick an answer again pls help.

lara31 [8.8K]

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3 years ago

Which value is NOT a solution of 8x3 – 1 = 0?

Tpy6a [65]

Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.

Answer:

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Step-by-step explanation:

Considering the equation

$8x^3\:-\:1\:=\:0$

Steps to solve the equation

$8x^3-1=0$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}$

$8x^3-1+1=0+1$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{Divide\:both\:sides\:by\:}8$

$\frac{8x^3}{8}=\frac{1}{8}$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

$x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}$

So,

$x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$

Therefore,

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Keywords: solution, value

Learn more about equation solution from brainly.com/question/1679491

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7 0

3 years ago

Help me please! Literally don’t understand the question.

andrey2020 [161]

I think it's d hope it helps

6 0

3 years ago

Read 2 more answers