![2 a^{b} * 3a^{b}](https://tex.z-dn.net/?f=2%20a%5E%7Bb%7D%20%2A%203a%5E%7Bb%7D%20)
<span><span><span>2<span>(2^2)</span></span>(3)</span><span>(2^2)
</span></span><span><span><span>2<span>(2^2)</span></span>(3)</span><span>(2^2)
</span></span><span>=96</span>
There's a key problem in this question compelling you to actually rewrite it like that! Mathematically that is inaccurate and incorrect. If you do 72(8+19) it seems as if you are going to do 8+19*72 as in algebra whatever is outside the bracket is bound to go multiplied so technically (8+19)+72 would make more sense and the answer is
Using bidmas do the brackets first
8+19= 27
27+72=99
Answer:
111°
Step-by-step explanation:
- All these are parallel lines, so the 36° angle is equal to the 36° angle inside the big triangle because they are vertically opposite.
- Ignore the line cutting between 45° and the 30° and consider it as one triangle
- Add them to get 75°
- Now you have two known angles 75° and 36°
- To get angle <em>x</em><em> </em>add 75° and 36° to get 111°
- Because x° is an exterior angle and exterior angles equal to the sum of interior angles opposite it inside the triangle.