Answer:
a tube contains 3 tennis balls how many tennis balls are there in 32 tubes
Answer:
• 9(sin 42°)
_______
sin 29°
Step-by-step explanation:
we know that
Applying the law of sines
Answer:
x/y=2/9
y = 9/2 x
Step-by-step explanation:
hope it's helpful ❤❤ THANK YOU.
Answer:
129 square foot
Step-by-step explanation:
<u>Step 1: Convert height of the door to inches</u>
Height of the door = 10 feet 8 inches
1 feet = 12 inches
10 feet = y inches
<em>Cross Multiply</em>
y = 120 inches
Height of door in inches = 120 + 8 =128 inches
<u>Step 2: Find the surface area of one side of the door</u>
Surface area = length x width
length = 128 inches
width = 145 inches
Surface area = 128 x 145
Surface area = 18560 inches
<u>Step 3: Convert surface area from inches to square foot</u>
Surface area = 18560 inches
1 square foot = 144 inches
y = 18560 inches
<em>Cross multiply</em>
144y = 18560
y = 18560/144
y = 128.89 rounded off to 129 square foot.
Therefore, you should report 129 square foot surface area to the hardware store.
!!
Answer:
The diagram for the question is missing, but I found an appropriate diagram fo the question:
Proof:
since OC = CD = 297mm Therefore, Δ OCD is an isoscless triangle
∠BCO = 45°
∠BOC = 45°
∠PCO = 45°
∠POC = 45°
∠DOP = 22.5°
∠PDO = 67.5°
∠ADO = 22.5°
∠AOD = 67.5°
Step-by-step explanation:
Given:
AB = CD = 297 mm
AD = BC = 210 mm
BCPO is a square
∴ BC = OP = CP = OB = 210mm
Solving for OC
OCB is a right anlgled triangle
using Pythagoras theorem
(Hypotenuse)² = Sum of square of the other two sides
(OC)² = (OB)² + (BC)²
(OC)² = 210² + 210²
(OC)² = 44100 + 44100
OC = √(88200
OC = 296.98 = 297
OC = 297mm
An isosceless tringle is a triangle that has two equal sides
Therefore for △OCD
CD = OC = 297mm; Hence, △OCD is an isosceless triangle.
The marked angles are not given in the diagram, but I am assuming it is all the angles other than the 90° angles
Since BC = OB = 210mm
∠BCO = ∠BOC
since sum of angles in a triangle = 180°
∠BCO + ∠BOC + 90 = 180
(∠BCO + ∠BOC) = 180 - 90
(∠BCO + ∠BOC) = 90°
since ∠BCO = ∠BOC
∴ ∠BCO = ∠BOC = 90/2 = 45
∴ ∠BCO = 45°
∠BOC = 45°
∠PCO = 45°
∠POC = 45°
For ΔOPD
Note that DP = 297 - 210 = 87mm
∠PDO + ∠DOP + 90 = 180
∠PDO + 22.5 + 90 = 180
∠PDO = 180 - 90 - 22.5
∠PDO = 67.5°
∠ADO = 22.5° (alternate to ∠DOP)
∠AOD = 67.5° (Alternate to ∠PDO)