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3 years ago

Summarize the feedback loop (transfer of energy) between the microbes and the mushrooms. (Video #1)

Chemistry

1 answer:

netineya [11]3 years ago

5 0

Answer:

Cyanobacteria, Azotobactor and Azospirillum are the microbes which is required for nitrogen cycle.

Explanation:

Nitrogen Cycle is a type of cycle in which nitrogen moves from atmosphere to the earth surface and again return back to the atmosphere. Cyanobacteria, Azotobactor and Azospirillum are the microbes which is required for nitrogen cycle. If these microbes is vanished from the environment, the nitrogen cannot be converted into other forms. Carbon is present in the atmosphere in carbondioxide form. This CO2 is used by the plants from atmosphere and make food from it. When these plants are eaten by animals, this CO2 is again release in the atmosphere. Due to global warming, the microbes present in the soil die due to increase in temperature of the soil. Levels of CO2 and CH4 increases if the soil warms up. With the increase in temperature, soil respiration increases which leads to more emission of CO2 and as a result more global warming occurs.

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If 3 newton's of force is pulling

Troyanec [42]

A. There is no movement
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3 years ago

What is the density of a sample of a substance with a volume of 120ml<br> and a mass of 90g?

tigry1 [53]

Answer:

<h3>The answer is 0.75 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 90 g

volume = 120 mL

We have

$density = \frac{90}{120} = \frac{9}{12} = \frac{3}{4} \\$

We have the final answer as

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2 years ago

Give the electronic configuration of carbon atom.

zimovet [89]

Answer:

1s2 2s2 2p2

Explanation:

it has 6 electrons in two energy levels so the sub levels are 1s, 2s and 2p

4 0

2 years ago

What is the electron arrangement for aluminum?

AlladinOne [14]

2,8,3 because Aluminium has the Atomic Number 13

3 0

3 years ago

What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91

Vikentia [17]

Answer: A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen $(O_2)$ if it occupies 31.6 mL at $91^{o}C$ .

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

$1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L$

Temperature = $91^{o}C = (91 + 273) K = 364 K$

As molar mass of $O_2$ is 32 g/mol. Hence, the number of moles of $O_2$ are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol$

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

$PV = nRT\\P \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm$

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen $(O_2)$ if it occupies 31.6 mL at $91^{o}C$ .

4 0

3 years ago