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3 years ago

From where does the nitrogen in the nitrogen cycle originate?

1 answer:

7 0

The correct answer is B. The nitrogen in the nitrogen cycle originate from the atmosphere. It forms approximately 78% of the Earth's atmosphere. However, this form is not usable because it is in its most stable form therefore unreactive. This nitrogen gas needs to be converted into nitrate compound for it to be usable. Then, the nitrogen cycle starts.<span />

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In what direction does an applied force move an object?

igor_vitrenko [27]

The answer is B. In the same direction as the force. Hope this helps :)

8 0

3 years ago

Glycerine is viscous than water?why

Sloan [31]

Answer:

Yes

Explanation:

Why is glycerol more viscous than water?

The glycerine is more viscous than water because due to presence of hydrogen atoms , we all know that glycerine has more hydrogen bonding than water molecule , which makes an aggregation which means that glycerine is more viscous than water , in simple words glycerine can't flow as that of water molecule.

7 0

2 years ago

At what temperature will 0.654 moles of helium gas occupy 12.30 liters at 1.95 atmospheres

pshichka [43]

Answer:

477 K

Explanation:

8 0

3 years ago

draw the lewis structure for CO2, H2CO3, HCO3-, and CO3 2-.Rank these in order of increasing attraction to water molecules. Expl

gavmur [86]

Answer:

The structures are attached in file.

Hydrogen bonding and intermolecular forces is the reason for ranks allotted.

Explanation:

In determining Lewis structure, we calculate the overall number of valence electrons available for bonding. Making carbon (the least electronegative atom) the central atom in the structure, we allocate valence electrons until each atom has achieved stability.

In order of decreasing affinity to water molecules:

$CO_{3}^{2-} > HCO_{3} ^{2-} > H_{2} CO_{3}$

This is due to the fact that the $CO_{3}^{2-}$ will accept protons more readily than the bicarbonate ion, $HCO_{3} ^{2-}$ . Carbonic acid, $H_{2} CO_{3}$ will not accept any more protons, hence it is the least attractive to water molecule, even though soluble.

3 0

3 years ago

Please help with #2 and #3

Vaselesa [24]

Answer:

2. $V_2=17L$

3. $V=82.9L$

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

$\frac{V_2}{T_2}=\frac{V_1}{T_1}$

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

$V_2=\frac{V_1T_2}{T_1}$

Therefore, we plug in the given data to obtain:

$V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L$

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

$V=\frac{nRT}{P}$

Therefore, we plug in the data to obtain:

$V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L$

Best regards!

6 0

3 years ago