3 years ago

Why do particles in a matter vibrate/move?

Chemistry

2 answers:

makkiz [27]3 years ago

7 0

Answer:

energy!!

Explanation:

loris [4]3 years ago

3 0

Answer:

Explanation:

force

You might be interested in

Determine molar mass of Mn (ClO3)3

goldenfox [79]

M(Mn(ClO3)3)=(54.938)+(35.45x3)+(15.999x9)
M(Mn(ClO3)3)=305.279 g/mol

8 0

3 years ago

What does B represent?

Mashutka [201]

Answer: Botanical Acid

Explanation:

8 0

3 years ago

A radioactive isotope X has a half-life of 36 years. How much X would remain after 108 years, if we started with 500 grams? A. 2

givi [52]

C. 62.5 I guess lol I hate chemistry

4 0

3 years ago

A rectangular solid has a length of 3 cm, a height of 4 cm and a

Artyom0805 [142]

Answer:

$60 cm^{3}$

Explanation:

volume=lwh

v=3*5*4

v= $60 cm^{3}$

4 0

3 years ago

At a certain temperature, 0.660 mol SO 3 is placed in a 4.00 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil

svet-max [94.6K]

Answer:

$Kc=6.875x10^{-3}$

Explanation:

Hello,

In this case, for the given chemical reaction at equilibrium:

$2 SO_3 ( g ) \rightleftharpoons 2 SO_ 2 ( g ) + O_ 2 ( g )$

The initial concentration of sulfur trioxide is:

$[SO_3]_0=\frac{0.660mol}{4.00L}=0.165M$

Hence, the law of mass action to compute Kc results:

$Kc=\frac{[SO_2]^2[O_2]}{[SO_3]^2}$

In such a way, in terms of the change $x$ due to the reaction extent, by using the ICE method, it is modified as:

$Kc=\frac{(2x)^2*x}{(0.165-2x)^2}$

In that case, as at equilibrium 0.11 moles of oxygen are present, $x$ equals:

$x=[O_2]=\frac{0.110mol}{4.00L}=0.0275M$

Therefore, the equilibrium constant finally turns out:

$Kc=\frac{(2*0.0275)^2*0.0275}{(0.165-2*0.0275)^2} \\\\Kc=6.875x10^{-3}$

Best regards.

6 0

3 years ago

Why do particles in a matter vibrate/move?​

Why do particles in a matter vibrate/move?