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sesenic [268]
3 years ago
6

Will give Brainliest!!! Will award answer! The following reaction shows the products when sulfuric acid and aluminum hydroxide r

eact.
2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

The table shows the calculated amounts of reactants and products when the reaction was conducted in a laboratory.

Initial Mass and Yield
Sulfuric Acid Aluminum Hydroxide
Initial Amount of Reactant 40 g 45 g
Theoretical Yield of Water from Reactant 14.69 g 31.15 g
Thank you for helping me learn about chemistry and apply skills.

What is the approximate amount of the leftover reactant? (4 points)
20.89 g of sulfuric acid
22.44 g of sulfuric acid
21.22 g of aluminum hydroxide
23.78 g of aluminum hydroxide
Chemistry
2 answers:
kap26 [50]3 years ago
8 0

Answer;

23.78g of aluminum hydroxide

Explanation:

DochEvi [55]3 years ago
6 0

Answer:

23.78 Grams of Aluminum Hydroxide

Explanation:

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Answer:

84.4g of AgCl

Explanation:

Based on the reaction:

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂

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<em />

100g of each reactant are:

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<em></em>

0.589 moles of AgNO₃ produce:

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4 years ago
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The answer to your question is:

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