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3 years ago

Evaluate the function rule for the given value. Y=12×3^x for x=-2

Mathematics

1 answer:

Alinara [238K]3 years ago

8 0

Answer:

Y = 4/3

Step-by-step explanation:

Solve for Y:

3 Y = 4

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 3 Y = 4 by 3:

(3 Y)/3 = 4/3

Hint: | Any nonzero number divided by itself is one.

3/3 = 1:

Answer: Y = 4/3

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Use the above graph to answer the following question. Which line indicates the demand curve? (1 point)

IRINA_888 [86]

Answer:

A - one

Step-by-step explanation:

A typical demand curve, in economics, depicts the relationship between price of a commodity on the y-axis, and quantity demanded on the x-axis.

The demand curve obeys the Law of Demand, which states that the higher the price, the lower the quantity demanded of that commodity, and vice versa, all things being equal. Thus, a typical demand curve will slope downwards, from left to the right.

Therefore, line 1 indicates the demand curve.

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3 years ago

All four sided polygons are quadrilaterals

Sati [7]

This is a true statement (:

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3 years ago

(3 x 10-7) x (8 x 10 )

charle [14.2K]

Answer:

1840

Step-by-step explanation:

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3 years ago

Read 2 more answers

An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen

devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 441

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 14.34

n = sample size = 16

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.131 < $t_1_5$ < 2.131) = 0.95 {As the critical value of t at 15 degrees of

freedom are -2.131 & 2.131 with P = 2.5%}

P(-2.131 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.131) = 0.95

P( $-2.131 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.131 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.131 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X -2.131 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.131 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $441-2.131 \times {\frac{14.34}{\sqrt{16} } }$ , $441+2.131 \times {\frac{14.34}{\sqrt{16} } }$ ]

= [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0

3 years ago

Are the triangles shown congruent?

boyakko [2]

Answer:

the second one i think

Step-by-step explanation:

because both have 2 sides with 1 angle

5 0

3 years ago