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Eduardwww [97]
3 years ago
10

Problem 1 Observer A, who is at rest in the laboratory, is studying a particle that is moving through the laboratory at a speed

of 0.624c and determines its lifetime to be 159 ns. (a) Observer A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory
Physics
1 answer:
ANTONII [103]3 years ago
3 0

Answer:

markers are 29.76 m far apart in the laboratory

Explanation:

Given the data in the question;

speed of particle = 0.624c

lifetime = 159 ns = 1.59 × 10⁻⁷ s

we know that; c is speed of light which is equal to 3 × 10⁸ m/s

we know that

distance = vt

or s = ut

so we substitute

distance = 0.624c × 1.59 × 10⁻⁷ s

distance = 0.624(3 × 10⁸ m/s) × 1.59 × 10⁻⁷ s

distance = 1.872 × 10⁸ m/s × 1.59 × 10⁻⁷ s

distance =  29.76 m

Therefore, markers are 29.76 m far apart in the laboratory

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mass of the first car, m₁ = 1000 kg

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mass of the second car, m₂ = 1200 kg

initial velocity of the second car, u₂ = 30 m/s

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P₁ = m₁u₁  +  m₂u₂

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P₂ = v(m₁ + m₂)

To determine "v" apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁  +  m₂u₂  = v(m₁  + m₂)

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v = 61,000/2,200

v = 27.727 m/s

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