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KengaRu [80]
3 years ago
11

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS AND I NEED ALL CORRECT ANSWERS ONLY!!!

Physics
2 answers:
Dominik [7]3 years ago
7 0

the purpose of fuses and circuit breakers is (first answer)

Montano1993 [528]3 years ago
7 0

Answer:the answer is # 1.

Explanation:fuses and circuit breakers have a smaller wire inside of them than the original cord or unit it is connected to. being the weakest conducter, the current will fry the fuse so it doesn't damage the unit it is connected to.

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An air gun fires 2 gram pellets at 60 m/s at a 45 gram golfball initially at rest. The pellets rebound at a speed 40 m/s and are
snow_lady [41]

Answer:

0.16 kgm/s

Explanation:

m_1 = Mass of pellet = 2 g

m_2 = Mass of golf ball = 45 g

u_1 = Initial Velocity of pellet  = 60 m/s

u_2 = Initial Velocity of golf ball = 0 m/s

v_1 = Final Velocity of pellet = 40 m/s

v_2 = Final Velocity of golf ball

In this system the linear momentum is conserved

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\Rightarrow m_2v_2=m_1u_1+m_2u_2-m_1v_1\\\Rightarrow m_2v_2=0.002\times 60+0-0.002\times 40\\\Rightarrow m_2v_2=0.04

As the golf ball is being shot 4 times every second the momentum delivered to the golf ball each second is 4\times 0.04=0.16\ kgm/s

8 0
3 years ago
SOMEONE HELP PLEASE 20 POINTS
VashaNatasha [74]
Question three is C and question 4 is b

3 0
3 years ago
Read 2 more answers
A space ship has four thrusters positioned on the top and bottom, and left and right as shown below. The thrusters can be operat
Ugo [173]

Answer:

The correct answer is - c.  Spaceship will have a velocity to the East and will be slowing down.

Explanation:

In this case, if turned on thruster #2 then it will exert force on the west side as thruster 2 is on the east side and it can be understood by Newton's third law that says each action has the same but opposite reaction.

As the spaceship engine applies force on the east side then according to the law the exhauster gas applies on towards west direction. It will try to decrease the velocity of the spaceship however, the direction of floating still be east side initally.

8 0
3 years ago
If a conducting loop of radius 10 cm is onboard an instrument on Jupiter at 45 degree latitude, and is rotating with a frequency
Pepsi [2]

Answer:

a)  fem = - 2.1514 10⁻⁴ V,  b) I = - 64.0 10⁻³ A, c)    P = 1.38  10⁻⁶ W

Explanation:

This exercise is about Faraday's law

         fem = - \frac{ d \Phi_B}{dt}

where the magnetic flux is

        Ф = B x A

the bold are vectors

        A = π r²

we assume that the angle between the magnetic field and the normal to the area is zero

         fem = - B π 2r dr/dt = - 2π B r v

linear and angular velocity are related

        v = w r

        w = 2π f

        v = 2π f r

we substitute

        fem = - 2π B r (2π f r)

        fem = -4π² B f r²

For the magnetic field of Jupiter we use the equatorial field B = 428 10⁻⁶T

we reduce the magnitudes to the SI system

       f = 2 rev / s (2π rad / 1 rev) = 4π Hz

we calculate

       fem = - 4π² 428 10⁻⁶ 4π 0.10²

       fem = - 16π³ 428 10⁻⁶ 0.010

       fem = - 2.1514 10⁻⁴ V

for the current let's use Ohm's law

        V = I R

        I = V / R

         I = -2.1514 10⁻⁴ / 0.00336

         I = - 64.0 10⁻³ A

Electric power is

        P = V I

        P = 2.1514 10⁻⁴ 64.0 10⁻³

        P = 1.38  10⁻⁶ W

6 0
3 years ago
The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla
Rama09 [41]
Please elaborate more on your question so I can help you
7 0
3 years ago
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