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Varvara68 [4.7K]
3 years ago
12

PLEASE SOMEONE! The density of the acetic acid solution is 1.05 g/mL. Calculate the %(m/m) of the acetic acid solution (convert

mol/L to %(m/m)).
CH3COOH(aq) + NaOH(aq) = CH3COOHNa(aq) + H2O(L)
Volume of CH3COOH = 0.1L
Titration Equation: CH3COOH(aq) + NaOH(aq) = CH3COOHNa(aq) + H2O(L)
Concentration of CH3COOH = 0.243 mol/L
Chemistry
1 answer:
tigry1 [53]3 years ago
8 0

Answer:

The Percentage concentration of acetic acid = 1.39 %

Explanation:

Density of acetic acid solution = 1.05 g/mL

Volume of acetic acid solution = 0.1 L = 100 mL

From the formula, Density = mass / volume; mass = density × volume

Mass of acetic acid solution = 1.05 g/mL × 100 mL = 105 g

Molar concentration of acetic acid solution = 0.243 mol/L

Molar mass of acetic acid, CH₃COOH = (12 × 2 + 1 ×4 + 16 ×2) = 60 g/mol

From the formula, mass concentration = molar concentration × molar mass

Mass concentration of acetic acid, CH₃COOH = 0.243 mol/L × 60 g/mol = 14.58 g/L

In one liter of acetic acid solution, there are 14.58 g of acetic acid. Therefore, in 0.1 L, there will be 14.58 × 0.1 = 1.458 g of acetic acid.

Percentage concentration of acetic acid = mass of acetic acid / mass of acetic acid solution × 100%

Percentage concentration of acetic acid = (1.458 / 105) × 100% = 1.39 %

The Percentage concentration of acetic acid = 1.39 %

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Hitman42 [59]

The mass of Ce(NO3)₄ that will be needed to create the solution was 24.16 g (in grams).

<h3>What exactly is the solution?</h3>

A homogenous mixture with one or even more solutes that have been dissolved in the solvent is known as a solution. The material that a solute dissolves in to create a homogenous mixture is known as a solvent. To create a homogenous mixture, a component must dissolve in a solvent.

<h3>What is an illustration of a solution?</h3>

One nanometer or smaller particles are referred to as a solution in a homogeneous mixture made up of two or more components. There are many different types of solutions, including sugar and salt solutions and fizzy water. Each component shows up as a different phase in a solution.

<h3>Briefing:</h3>

Mole of Ce(NO₃)₄ = 0.06225 mole

Molar of Ce(NO₃)₄ = 140.12 + 4[14 + (16×3)]

= 140.12 + 4[14 + 48]

= 140.12 + 4[62]

= 140.12 + 248

= 388.12 g/mol

Mass of Ce(NO₃)₄ = 0.06225 × 388.12

Mass of Ce(NO₃)₄ = 24.16 g

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4 0
1 year ago
a) Provide equation of K of this reaction, use symbol " ^ " for exponents. That means 1000 = 10^3 and 1/100 is 10^(-2). b) How m
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Answer and Explanation:

a. The equation of K of this reaction is shown below:-

3 A + 5 B + 4 C↔5 D + 7 E + F

K = \frac{(D)^5 (E)^7 (F)}{(A)^3 (B)^5 (C)^4}

b. The moles of compound F is shown below:-

3 A + 5 B + 4 C↔5 D + 7 E + F

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Now, the mole of produced is

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Now, we will the value of c by using the above equation

= \frac{1}{4} \times 2

After solving the above equation we will get

0.5 moles

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vredina [299]
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If all minerals are expressed by a specific chemical formula they have​
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All minerals have a chemical formula

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