Answer:
2.76×10⁻¹⁰ C
Explanation:
Applying,
V = W/q................... Equation 1
Where V = Electric Potential, E = Electric potential energy, q = charge.
make q the subject of the equation
q = W/V................ Equation 2
From the question,
Given: W = 4.26×10⁻⁸ J, V = 154.5 V
Substitute these values into equation 2
q = 4.26×10⁻⁸/154.5
q = 2.76×10⁻¹⁰ C
Answer:
D = 43 m
Explanation:
given,
initial velocity = 18 m/s
angle θ = 60°
total horizontal distance covered by the shell is

applying conservation of momentum in horizontal direction
m v₀ cos θ = m₁v₁ + m₂ v₂
m v₀ cos θ = 0.5 m v₂
v₂ = 2 v₀ cos θ.
distance covered by the shell from point of explosion
R' = v t
= 
=
= 
= R
total distance traveled by the shell is
D = 
= 1.5 R
= 
D = 
= 42.9 ≅ 43 m
D = 43 m
Answer: the correct answer is 7.8026035971 x 10^(-13) joule
Explanation:
Use Energy Conservation. By ``alpha decay converts'', we mean that the parent particle turns into an alpha particle and daughter particles. Adding the mass of the alpha and daughter radon, we get
m = 4.00260 u + 222.01757 u = 226.02017 u .
The parent had a mass of 226.02540 u, so clearly some mass has gone somewhere. The amount of the missing mass is
Delta m = 226.02540 u - 226.02017 u = 0.00523 u ,
which is equivalent to an energy change of
Delta E = (0.00523 u)*(931.5MeV/1u)
Delta E = 4.87 MeV
Converting 4.87 MeV to Joules
1 joule [J] = 6241506363094 mega-electrón voltio [MeV]
4 mega-electrón voltio = 6.40870932 x 10^(-13) joule
4.87 mega-electrón voltio = 7.8026035971 x 10^(-13) joule