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Black_prince [1.1K]
3 years ago
12

A suitcase has a width of 55 cm. Which unit conversation fraction should you use to find the width in inches?

Physics
1 answer:
Crank3 years ago
6 0

Answer:

2,54 cm are equal to 1 inch

Explanation:

Doing the conversion:

55[cm]*\frac{1[inch]}{2,54[cm]} =21,65[inch]

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The Milky Way is our Galax. Where are we located in Milky Way?​
Anuta_ua [19.1K]

Earth is located in one of the spiral arms of the Milky Way (called the Orion Arm) which lies about two-thirds of the way out from the center of the Galaxy.

4 0
3 years ago
_____is the nitrogen base found only in DNA.
Vesna [10]

Answer:

thymine

Explanation:

The nitrogen base found only in DNA is known as thymine which is also called 5-methyl uracil as thymine is a derivative of uracil.

6 0
3 years ago
4. For a series of experimentally measured values give the definition of (a) average or mean value (b) the deviation from the me
Naya [18.7K]

Answer:

a)   x_average = ∑ x_{i} / n , b) Δx_{i} = x_{i} –x_average,

d) σ = √(1/n-1  ∑ Dx_{i}² )

Explanation:

Some definitions are requested

a) the average value is the sum of all the values ​​divided by the number of them, if the uncertainties are random, this is the closest value to the real one

       x_average = ∑ x_{i} / n

b) The deviation from the mean value or absolute error is the measured value minus the average value

       Δx_{i} = x_{i} –x_average

c) is the average value of the deviations

        Δx_average = ∑ Δx_{i} / n

d) It is a measure of the dispersion of the values ​​with respect to their average value, it takes the worst of all cases, widely used for large numbers of data

          σ = √(1/n-1  ∑ Dx_{i}² )

Experimental results should be given as follows

  Average value ± uncertainty and the standard deviation

  (x_average + - Δx_average)

  σ

3 0
3 years ago
An object of height 2.7 cm is placed 29 cm in front of a diverging lens of focal length 16 cm. Behind the diverging lens, and 12
kati45 [8]

Answer:

A)  q = -8.488 cm ,  B)  m = 0.29

Explanation:

A) For this exercise in geometric optics, we will use the equation of the constructor

          \frac{1}{f} = \frac{1}{p} +  \frac{1}{q}

where p and q are the distance to the object and image, respectively and f is the focal length

in our case the distance the object is p = 29 cm the focal length of a diverging lens is negative and indicates that it is f = - 12 cm

         \frac{1}{q} = \frac{1}{f} - \frac{1}{p}

     

we calculate

          \frac{1}{q} = - \frac{1}{12} - \frac{1}{29}

          \frac{1}{q} = - 0.1178

          q = -8.488 cm

the negative sign indicates that the image is virtual

B) the magnification is given

          m = \frac{h'}{h} = - \frac{q}{p}

       

we substitute

          m = - \frac{-8.488}{29}

          m = 0.29

the positive sign indicates that the image is right

4 0
3 years ago
Derive the formula 2as=v² -u² where the formula have have usual meanings
attashe74 [19]

Answer:The main formula is v² = u² + 2as

Explanation:

S=½(u +v)t

t = v+u/a

S=½(v-u)(v+u/a)

S=½v²+uv-uv-u²/a

2as=v²-u²

5 0
3 years ago
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