Answer:
statement - 'The work done by friction is equal to the sum of the work done by the gravity and the initial push' is correct.
Explanation:
The statement ''The work done by friction is equal to the sum of the work done by the gravity and the initial push" is correct.
The above statement is correct because, the initial push will tend to slide down the block thus the work done by the initial push will be in the downward direction. Also, the gravity always acts in the downward direction. thus, the work done done by the gravity will also be in the downward direction
here, the downward direction signifies the downward motion parallel to the inclined plane.
Now we know that the work done by the friction is against the direction of motion. Thus, the friction force will tend to move the block up parallel to the inclined plane.
Hence, for the block to stop sliding the the above statement should be true.
Im a jewish salesman wanting to know if you wanted to buy some jesus movies
Do you want me to translate it?
Answer:
11.5
Explanation:
you do 12(sin 73.3) because its on the y you do sin
Answer:
1547.6 J
Explanation:
From the law of conservation of energy, the sum of initial and final energy is the same. Energy can only be transformed into other forms but can't be created nor lost
Initial kinetic energy of the hammer system is given by
where m is mass of the body and v is the velocity
Substituting m for mass of hammer which is 2.44 Kg and v for 62 m/s
![KE_i=0.5*2.44 Kg*(62 m/s)^{2}=4689.68 J](https://tex.z-dn.net/?f=KE_i%3D0.5%2A2.44%20Kg%2A%2862%20m%2Fs%29%5E%7B2%7D%3D4689.68%20J)
Since the hammer comes to rest, the final kinetic energy is zero since it's velocity is zero
![KE_f=0 J](https://tex.z-dn.net/?f=KE_f%3D0%20J)
Change in kinetic energy is given by
hence 0-4689.68 J=-4689.68 J
Change in total internal energy is given by
and in this case the change in potential energy is zero
![\triangle PE-\triangle KE=0--4689.68 J=4689.68 J](https://tex.z-dn.net/?f=%5Ctriangle%20PE-%5Ctriangle%20KE%3D0--4689.68%20J%3D4689.68%20J)
Since only 0.33 of this energy is converted hence
![0.33\times4689.68 J=1547.5944 J\approx 1547.6 J](https://tex.z-dn.net/?f=0.33%5Ctimes4689.68%20J%3D1547.5944%20J%5Capprox%201547.6%20J)