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3 years ago

how many moles of barium hydroxide, Ba(OH2), would be required to react with 117 g hydrogen bromide, HBr?

Chemistry

2 answers:

Mariulka [41]3 years ago

7 0

Answer:

0.726

Explanation:

Kisachek [45]3 years ago

4 0

The moles of Ba(OH)2 that is required to react with 117 HBr is calculated as below

find the moles of HBr used
mass/ molar mass = 117 g/ 80.9 g/mol = 1.446 moles

write the reacting equation

Ba(OH)2 + 2 HBr = BaBr2 + 2 H2O

by use of mole ratio of Ba(OH)2 : HBr which is 1:2 the moles of Ba(OH)2 is therefore
= 1.446 moles x1/2 = 0.723 moles of Ba(OH)2

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At room temperature (20°C} and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha

Alekssandra [29.7K]

Explanation:

$Density =\frac{Mass}[Volume}$

Density of the air ,d= 1.189 g/L

(a) Density of the evacuated ball

Mass of the ball ,m = 0.12 g

Volume of the ball = $V=560 cm^3=560 ml=0.560 L$

$D =\frac{0.12 g}{0.560 L}=0.214 g/L$

D<d, teh evacuated ball will flaot in air.

(b) Density of the evacuated ball D = 0.214 g/L

Density of carbon dioxide gas = $d_1=1.830 g/L$

Mass of the carbon dioxide gas :

$1.830 g/L\times 0.560 L=1.0248 g$

Total density of filled ball with carbon dioxide gas:

$\frac{0.12 g+1.0248 g}{0.560 L}==2.044 g/L$

The ball filled with carbon dioxide will not float in the air because total density of filled ball is greater than the density of an air.

(c) Density of the evacuated ball D = 0.214 g/L

Density of hydrogen gas = $d_2=0.0899 g/L$

Mass of the hydrogen gas :

$1.830 g/L\times 0.560 L=0.050344 g$

Total density of filled ball with hydrogen gas:

$\frac{0.12 g+0.050344 g}{0.560 L}==0.3041 g/L$

The ball filled with hydrogen will float in the air because total density of filled ball is lessor than the density of an air.

(d) Density of the evacuated ball D = 0.214 g/L

Density of oxygen gas = $d_3=1.330 g/L$

Mass of the oxygen gas :

$1.330 g/L\times 0.560 L=1.7448 g$

Total density of filled ball with oxygen gas:

$\frac{0.12 g+1.7448 g}{0.560 L}=1.5442 g/L$

The ball filled with oxygen will not float in the air because total density of filled ball is greater than the density of an air.

(e) Density of the evacuated ball D = 0.214 g/L

Density of nitrogen gas = $d_4=1.165 g/L$

Mass of the nitrogen gas :

$1.165 g/L\times 0.560 L=0.6524 g$

Total density of filled ball with nitrogen gas:

$\frac{0.12 g+0.6524 g}{0.560 L}==1.3792 g/L$

The ball filled with nitrogen will not float in the air because total density of filled ball is greater than the density of an air.

f) Mass must be added to sink the ball = m

Density of ball > Density of the air ; to sink the ball.

$\frac{0.12g +m}{0.560L}>1.189 g/L$

m > 0.54584 g

For any case weight added to ball to make it sink in an air should be grater than the value of 0.54584 grams.

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Based on the greenhouse effect, if the amount of carbon dioxide in the air decreased, what would happen?

choli [55]

A) the average global temp. Would decrease

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What causes some aqueous solutions to have a low PH?

noname [10]

Low pH means the solution is acidic; if the solution is acidic, that means that there are hydronium ions in solution (H3O+). For example, hydrochloric acid dissolves into H+ ions and Cl- ions, and the H+ ions rreact with water like this:
H+ + H2O --> H3O+

If you want to get mathematical, pH is defined as the negative log of the concentration of hydronium ions.
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How does nuclear reactor produce electricty

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3 years ago

A red blood cell is placed into each of the following solutions. Indicate whether crenation, hemolysis, or neither will occur. S

Burka [1]

Answer:

Solution A: crenation

Solution B: hemolysis

Solution C: hemolysis

Solution D: crenation

Solution E: crenation

Explanation:

Hemolysis is the rupturing of red blood cells, which results in the release of hemoglobin (from within the red blood cells) into the plasma. If a red blood cell is placed in a hypotonic solution, water will flow into the cell, the cell will swell and hemolysis will.

Crenation: when a red blood cell is placed in a hypertonic solution (such as highly saline solution), the red blood cell will lose water(osmosis) and will shrink in size. The red blood cell has undergone crenation.

In order for a red blood cell to prevent from undergoing hemolysis or crenation, the cell must be placed in an isotonic solution, i.e either in 0.9% (m/v) NaCl solution or 5% glucose solution

Solution B and Solution C are hypotonic solution, thus red blood cell has undergone hemolysis.
Solution A, D and E are hypertonic solution. thus red blood cell has undergone crenation

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3 years ago