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Elza [17]
2 years ago
15

Form a bond: Each electron has a charge of 1–, and each proton has a charge of 1+. You can calculate the charge of an atom by su

btracting the number of electrons from the number of protons. Move an electron from the sodium to the chlorine atom
Chemistry
2 answers:
dimaraw [331]2 years ago
7 0

Answer:

A.What are the charges of each atom now?

Sodium: +1___ Chlorine: __-1___

Turn on Show charge to check. These charged atoms are called ions.

B.Is each ion stable? Explain.

-Electromagnetic force pulls them together

Shtirlitz [24]2 years ago
5 0

Explanation:

Bond forming:

   Given species:

             Na - Sodium              Cl - Chlorine

 Na has a valence electron  

 Cl has 7 valence electron

To form a bond of this nature, there must be a transfer of electrons.

 Here, the bond is between a metal and non-metal

The metal is sodium and the non-metal is chlorine;

  Na         →     Na⁺  +   e⁻                                           loss of 1 electron

2,8,1               2,8

                  isoelectronic with Neon

Cl  + e  →   Cl⁻                                                              gain of one electron

               isoelectronic with Argon

  Na⁺  +  Cl⁻   →   Na⁺.Cl⁻

  This bond type is an ionic bond

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telo118 [61]

Answer:

Follows are the solution to the given question:

Explanation:

Dry Soil weight = solid soil weight = 284 \ grams

solid soil volume =205 \ cc

saturated mass soil = 361 \ g

The weight of the soil after drainage is =295 \ g

Water weight for soil saturation = (361-284) = 77 \ g

Water volume required for soil saturation =\frac{77}{1} = 77 \ cc

Sample volume of water: = \frac{\text{water density}}{\text{water density input}}

= 361- 295 \\\\ = 66 \ cc

Soil water retained volume = (draining field weight - dry soil weight)

                                             = 295 - 284 \\\\ = 11 \ cc.

\text{POROSITY}= \frac{\text{Vehicle volume}}{\text{total volume Soil}}

                    = \frac{77}{(205 + 77)}  \\\\= \frac{77}{(282)}  \\\\ = 27.30 \%

(Its saturated water volume is equal to the volume of voids)

\text{YIELD SPECIFIC} = \frac{\text{Soil water volume}}{\text{Soil volume total}}

                              = \frac{66}{(205+77)}\\\\= \frac{66}{(282)}\\\\=0.2340\\\\ = 0.23

\text{Specific Retention}= \frac{\text{Volume of soil water}}{\text{Total soil volume}}

                            = \frac{11}{282} \\\\= 0.0390 \\\\ = 0.04

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Answer:

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Lina20 [59]

Answer:

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Hope this helps, thank you :) and I am not sure about magnitude I think you can that since there is greater force on the right side, there is more magnitude there.

4 0
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